Question

我必须编写一个程序，按字母顺序升序读取和显示文本文件中的所有单词。文本文件作为命令行参数传递。程序还必须有一个输入框，提交按钮，结果显示在同一窗口下面。

我编辑了程序并将其清理干净。删除了filename方法并调用了button方法以使其更简单并尝试使提交按钮起作用。然而，似乎没有任何改变。一切都工作到我按下提交按钮，然后没有任何反应。

    import java.io.*;
import java.util.*;
import javafx.application.Application;
import javafx.geometry.Pos;
import javafx.stage.Stage;
import javafx.scene.Scene;
import javafx.scene.layout.BorderPane;
import javafx.scene.layout.HBox;
import javafx.scene.text.Text;
import javafx.scene.control.Button;
import javafx.scene.control.TextField;
import javafx.scene.control.TextArea;

public class AlphabeticalOrder extends Application {

   TextField fileName = new TextField();
   Button submitButton = new Button("Submit");
   TextArea outputArea = new TextArea();

   public void button() {
       submitButton.setOnAction(e -> {
           if(fileName.getText().length() > 0) {
               submitButtonClick();
           }
       });
   }

   @Override
   public void start(Stage primaryStage) {
       try {
           BorderPane root = new BorderPane();

           Scene scene = new Scene(root,400,400);

           primaryStage.show();

           // Set the stage title
           primaryStage.setTitle("AlphabeticalOrder");

           // Place the scene in the stage
           primaryStage.setScene(scene);

           // Display the stage
           primaryStage.show();

           // Hold a button in an HBox
           HBox inputBox = new HBox();
           inputBox.setSpacing(10);
           inputBox.setAlignment(Pos.CENTER);
           inputBox.getChildren().addAll(new Text("Filename:"));
           inputBox.getChildren().addAll(fileName);
           inputBox.getChildren().addAll(submitButton);
           root.setTop(inputBox);

           //This creates a text box to display the results
           //from reading the file in a pane
           outputArea.setStyle("-fx-text-fill: black");
           outputArea.setStyle("-fx-background-color: grey");
           root.setCenter(outputArea);
       } catch(Exception e) {
           button();
           e.printStackTrace();
       }
   }


   public void submitButtonClick() {
       if(fileName.getText().length() > 0) {
          File sourceFile = new File(fileName.getText());
         if (!sourceFile.exists()) {
             System.out.println("Source file " + fileName.getText()
                  + " does not exist");
          }
       }

       fileName.setText("Test 1");
   }

   class SortFile
   {
       //sorting function
   void sortArray(String array[]) {
       //Loop for no.of passes
   for(int i=0;i<array.length-1;i++)

       //Repeat no.of comparisons
       for(int j=0;j<array.length-i-1;j++)

           //Comparing adjacent elements
           if(array[j].compareTo(array[j+1])>0)
   {
               //Swap using temp variable
               String temp=array[j];
               array[j]=array[j+1];
               array[j+1]=temp;
              }
   }
   public void reader(String args[])
   {
       //Creating File object
       File freader;

       //Scanner for reading
       Scanner filescanner;

       //Array list for dynamic elements adding
   ArrayList <String> array = new ArrayList<String>();

   //If file name is no.of passed as argument is 1
   if(args.length==1)
   {
   try
   {
       //Create file object
       freader = new File(args[0]);

       //Reading from file
       filescanner = new Scanner(freader);

       //Reading until end of file
   while(filescanner.hasNext())
   {
       //Reading each word and to Array List
       array.add(filescanner.next());
   }
   }
   //If file IOException is thrown
      catch(IOException ie)
   {
   System.out.println(ie);
   }String[] newArray = new String[array.size()];

   //Convert Array list to ArraynewArray=array.toArray(newArray);

   System.out.println("List of strings from file Before Sorting : \n");

   //Print before sorting words
   for(int i=0;i<newArray.length;i++)
   System.out.print(newArray[i]+" ");

   //Call sorting method
   sortArray(newArray);
   System.out.println("\nList of strings from file After Sorting : \n");

   //Print after sorting words
   for(int i=0;i<newArray.length;i++)
   System.out.print(newArray[i]+" ");

   System.out.print("\n");
   }
   else
       //If file name is not passed as argument then show usage syntax
       System.out.println("Usage syntax: SoftFile <Words.rtf>");}
   }
   }

Answer 1

你永远不会将处理程序挂钩到你的提交按钮 - button这个函数只会被filename调用一次，而这个函数永远不会被调用。

编辑：我建议你花点时间阅读this tutorial。

Java FX，功能不正常

1 个答案: