Question

我发送一个请求来获取GeneralDictViewmodel对象及其字典，但它只获取自身，而不是它在AJAX响应中的字典。我该如何解决这个问题？

    $.ajax({
        url: getAllGeneralDictUrl,
        type: 'POST',
        cache: false,
        dataType: 'json',
        contentType: 'application/json; charset=utf-8',
        success: function (data, status, resObject) {
            alert("success..." + data); 

        },
        error: function (xhr) {
            alert(xhr.responseText);
        }
    });


    public JsonResult GetAllGeneralDict()
    { 
            GeneralDictServiceClient generalDictSvc = new GeneralDictServiceClient();
            GeneralDictViewModel generalDictRes = new GeneralDictViewModel();
            generalDictRes.ShipTypes = generalDictSvc.GetGeneralDict("SHIP_TYPE").ToDictionary(x => x.KEY_ITEM, x => x.VALUE_ITEM);
            generalDictRes.BodyMaterials = generalDictSvc.GetGeneralDict("BODY_MATERIAL").ToDictionary(x => x.KEY_ITEM, x => x.VALUE_ITEM);
            generalDictRes.Designations = generalDictSvc.GetGeneralDict("DESIGNATION").ToDictionary(x => x.KEY_ITEM, x => x.VALUE_ITEM);
             return Json(generalDictRes);
    }

Answer 1

首先，如果你要提取数据，你应该在你的ajax调用中“获取”。

try {
    $.ajax({
        url: 'template/GetAllGeneralDict',
        type: 'POST',
        cache: false,
        dataType: 'json',
        contentType: 'application/json; charset=utf-8',
        success: function (data, status, resObject) {
            alert("success..." + data);

        },
        error: function (xhr) {
            alert(xhr.responseText);
        }
    });
} catch (e) {
    window.location.href = SiteRootPath + "default.aspx";
    $('#loading').hide();
}

第二：您应该在Controller的返回函数中使用JSON数据编写JsonRequestBehavior.AllowGet

public JsonResult GetAllGeneralDict()
        {
            var abcObj = new Animal() { Id = 1, Name = "ZTom" };

            return Json(abcObj, JsonRequestBehavior.AllowGet);
        }

在AJAX响应中读取MVC模型

1 个答案: