Question

SELECT vhfloorno, 
       Count(ischeckin)  AS ChecKIn, 
       Count(ischeckout) AS CheckOut 
FROM   visitorhistory t1 
WHERE  ( Year(vhcheckinebi) = Year(@From) 
         AND Month(vhcheckinebi) = Month(@From) 
         AND Day(vhcheckinebi) = Day(@From) ) 
        OR ( Year(vhcheckoutebi) = Year(@To) 
             AND Month(vhcheckoutebi) = Month(@To) 
             AND Day(vhcheckoutebi) = Day(@To) ) 
GROUP  BY vhfloorno

我想在Floor的基础上显示一个表中的Check In和Check Out Visitors的计数，但是通过此查询，check in和check Out值是相同的。其中vhcheckinebi是访客入住时的日期时间，而vhcheckoutebi是访客结账时的日期时间。请帮帮我。

Answer 1

假设您的列ischeckin属于bit类型，您应该这样做使用SUM(CAST(ischeckin as INT))代替Count(ischeckin)，否则每次都会计算“false”和“true”值：

SELECT vhfloorno, 
       SUM(CAST(ischeckin as INT)) AS ChecKIn, 
       SUM(CAST(ischeckout as INT)) AS CheckOut 
FROM   visitorhistory t1 
WHERE ...

请参阅此处以获取最低示例：http://data.stackexchange.com/stackoverflow/query/477199/checkin-and-checkout-counts

Answer 2

可能你想要条件聚合：

SELECT vhfloorno, 
       sum(case when ischeckin = 1 then 1 else 0 end)  AS ChecKIn, 
       sum(case when ischeckout = 1 then 1 else 0 end) AS CheckOut 
FROM   visitorhistory t1 
...

我想从一张桌子上显示记录

2 个答案: