Question

我在C＃中创建了一个Web API，并从jquery调用该api，但收到错误：

('#buttonid').click(function (event) {
    $.ajax({
     method: "GET",url: "http://localhost:54580/api/persons",
     dataType: 'jsonp',
      beforeSend: function (request) {
                request.setRequestHeader("Authorization", "Negotiate");
            },
       async: true,
     success: function (data) {

     console.log(JSON.stringify(data));

    },
      error: function(jqXHR,error, errorThrown) {  
           if(jqXHR.status&&jqXHR.status==400){
                 console.log(jqXHR.responseText); 
           }else{
                console.log("Something went wrong");
           }
      }
}); 
});

在调试模式下，我能够看到我的数据。：

http://localhost:54580/api/persons?callback=jQuery111103874004708615564_1461475734608&_=1461475734609

数据是：

[{
    "FirstName": "Ramu",
    "LastName": "Rai",
    "Email": "test123"
}, {
    "FirstName": "Ramu1",
    "LastName": "Rai1",
    "Email": "test123"
}]

但代码永远不会成功。它总是打印出来＃34;出了问题＆＃34;

Answer 1

使用json代替jsonp，尝试下面的演示（替换网址）

＆＃13;

$.ajax({
  method: "GET",
  url: "http://jsonplaceholder.typicode.com/posts/1", //"http://localhost:54580/api/persons",
  beforeSend: function(request) {
    request.setRequestHeader("Authorization", "Negotiate");
  },
  success: function(data) {
    var result = JSON.stringify(data);
    var $result = document.querySelector('#pre');
    $result.textContent = result;
  },
  error: function(jqXHR, error, errorThrown) {
    if (jqXHR.status && jqXHR.status == 400) {
      console.log(jqXHR.responseText);
    } else {
      console.log("Something went wrong");
    }
  }
});
function my_function(data){
  console.log('my_function', data);
}

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<pre id="pre"></pre>

＆＃13;

在$ .ajax调用中收到错误

1 个答案: