我正在尝试打印我的数据并将其编码为JSON。我正在从我的MySQL数据库中提取数据以进行测验。我试图提取1个问题的数据,1个类别和4个选项来进行一组测验。我想我几乎得到了它如何使它工作,但我没有找到如何。这是link中的结果检查。 将JSON粘贴到此link,以便您可以轻松地格式化它。从那个JSON数据,我想为每个问题输出这样的结果:
"What is the approximate number of islands that comprise the Philippines?",
"Philippine Geography",
[
{
"quiz_choice_id":"5",
"choice":"7000",
"is_correct_choice":"1"
},
{
"quiz_choice_id":"6",
"choice":"6000",
"is_correct_choice":"0"
},
{
"quiz_choice_id":"7",
"choice":"8000",
"is_correct_choice":"0"
},
{
"quiz_choice_id":"8",
"choice":"9000",
"is_correct_choice":"0"
}
],
这是我的代码:
<?php
/**
* Created by PhpStorm.
* User: Muhammad
* Date: 19/04/2016
* Time: 00:46
*/
require_once('Database_Connect.php');
$questions_query = "SELECT question, quiz_choice_id, choice ,is_correct_choice, category FROM category_question cq, question q, question_choices qc WHERE q.quiz_question_id = qc.quiz_question_id AND q.cat_ques_id = cq.cat_ques_id LIMIT 10";
$questions_query_result = mysqli_query($con, $questions_query) or die("error loading questions");
$questions_results = array();
encode_result($questions_query_result);
function encode_result($result)
{
//$response = array();
$questions = array();
//$choices = array();
while ($r = mysqli_fetch_array($result)) {
//$response[] = $r;
//$questions = array('question' => $r[0]);
$questions[] = $r['question'];
$questions[] = $r[4];
$choices[] = array('quiz_choice_id' => $r[1], 'choice' => $r[2], 'is_correct_choice' => $r[3]);
$questions[] = $choices;
//array_push($questions, $questions['question']);
//array_push($questions_results, $questions);
}
echo json_encode(array('questions'=>$questions));
}
mysqli_close($con);
我找不到让它工作的方法,因为数据库quiz_choice_id,choice, is_correct_choice
位于不同的表中,但我将所有内容合并到一个表中,就像我在SQL语句$questions_query
中看到的那样。请让我知道如何解决这个问题。提前谢谢。
答案 0 :(得分:1)
你想让json看起来像这样吗?
[ {
"question" : "What is the approximate number of islands that comprise the Philippines?",
"category" : "Philippine Geography",
"choices" : [
{
"quiz_choice_id":"5",
"choice":"7000",
"is_correct_choice":"1"
},
{
"quiz_choice_id":"6",
"choice":"6000",
"is_correct_choice":"0"
},
{
"quiz_choice_id":"7",
"choice":"8000",
"is_correct_choice":"0"
},
{
"quiz_choice_id":"8",
"choice":"9000",
"is_correct_choice":"0"
}
]
},{
..... // next question
}]
你必须做这样的事情,但我不知道查询的结果是什么。
$questions = array();
while ($r = mysqli_fetch_array($result)) {
$key = $r['quiz_question_id']; // you need a key here that is unique to the question, so i think this will do looking at the schema you posted, this will group them in that segment of the array.
if( !isset( $questions[$key] ) ){
//if we never had this question, create the top level in the results
$questions[$key] = array(
'question' => $r['question'],
'category' => $r['category'],
'choices' => array()
);
}
//add in the choices for this question
//on the next iteration, the key is the same so we only do this part
//and append that rows choices to the previous data using $key to match the question
$questions[$key]['choices'][] = array('quiz_choice_id' => $r['quiz_choice_id'], 'choice' => $r['choice'], 'is_correct_choice' => $r['is_correct_choice']);
}
如果这是问题ID,唯一标识符,请务必在查询中添加quiz_question_id
。基本上这会将它们组合在一起,因为对于每个问题的选择,这将是相同的。
我在输出中添加了字符串键,我不会使用字符串键和编号索引进行混音。我希望我把它们映射出来。
此外,我还没有对此进行过测试,很抱歉,如果有任何语法错误。