Question

下面是我的PHP代码，目前，它显示所有错误等，但如果其中一个是正确的，它将提交表单，我如何更改我的代码，以便如果1不正确则不提交

<?php
$cusMsg = "";
$fNameMsg = "";

if (isset($_POST["submit"])) {  
    $id = $_POST["custid"];

    if(empty($id)) {
        $cusMsg = '<span class="error"> Field was left empty</span>';
    } else if(!is_numeric($id)) {
        $cusMsg = '<span class="error"> Customer ID must be numeric</span>';
    } else if(strlen($id) != 6) {
        $cusMsg = '<span class="error"> Customer ID must be 6 digits long</span>';
    } else {
        return true;
    }

}

if (isset($_POST["submit"])) {  
    $fName = $_POST["customerfname"];
    $pattern = "/^[a-zA-Z-]+$/";

    if(empty($fName)) {
        $fNameMsg = '<span class="error"> Field was left empty</span>';
    } else if(!preg_match($pattern, $fName)) {
        $fNameMsg = '<span class="error"> First name must only containt letters and hyphens</span>';
    } else if(strlen($fName) > 20) {
        $fNameMsg = '<span class="error"> First name must not be longer than 20 characters</span>';
    } else {
        return true;
    }

}

}
?>

Answer 1

而不是在最后一次使用，否则传递此

else if(!empty($fName) && preg_match($pattern, $fName) && strlen($fName) < 20){
return true;
}

它只是使用AND运算符检查所有条件，并且仅在满足所有条件时才返回true

Answer 2

默认情况下，您可以将标志变量$ submit设置为false。

if (isset($_POST["submit"])) {  

   $submit = false; // Add this

   $id = $_POST["custid"];

   if (empty($id)) {

       $cusMsg = '<span class="error"> Field was left empty</span>';

   } else if (!is_numeric($id)) {

       $cusMsg = '<span class="error"> Customer ID must be numeric</span>';

   } else if(strlen($id) != 6) {

        $cusMsg = '<span class="error"> Customer ID must be 6 digits long</span>';

   } else {

      $submit = true;
   }

  // Now check the value of $submit and write your code accordingly.

  if ($submit) {
     // Write your submit action
  } else {
     // Other action
  }

}

PHP，如果有错误，请不要提交

2 个答案: