Question

简单的php for循环，在添加循环之前工作正常，但我想要它打印4行3个产品。问题是它将所有12个项目放入一行！然后它会在页面底部再创建3个空行。

添加了代码的更新版本，认为它可能对其他人有所帮助，虽然它显示正确但我必须从表中提取15条记录。

<?php for($i = 0; $i < 4; $i++) { ?>
            <div class="row products">
                <?php while($product = mysqli_fetch_assoc($featured)) : ?>

                <!-- product-->
                <div class="col-md-4 col-sm-6">
                    <div class="product">
                        <div class="image">
                            <a href="#"><img src=" <?= "images/wheels/wheelphotos/". $product["bigpic"]; ?>" alt= "<?= $product["manufacturer"]; ?>" class="img-responsive"></a>
                            <div class="quick-view-button"><button type="button" onclick="quickModal(<?= $product["recid"]; ?>)"  class="btn btn-default btn-sm">Quick view</button></div>
                        </div>
                        <div class="text">
                            <p class="brand"><a href="#"><?= $product["manufacturer"]; ?></a></p>
                            <h3> <a href="detail.html"><?= $product["diam"]; ?></a></h3>
                            <p class="price">$<?= $product["rrp"]; ?></p>
                            <button class="btn btn-default btn-sm btn-primary">Details</button>
                        </div>
                    </div>
                </div>

                <?php endwhile; ?>
            </div>
            <?php } ?>


<?php for($i = 0; $i < 4; $i++) { ?>
            <div class="row products">
                <?php
                $j = 0;
                while($product = mysqli_fetch_assoc($featured)) :
                $j++;
                    if($j > 3 ){
                        break;
                    }
                ?>
                <!-- product-->
                <div class="col-md-4 col-sm-6">
                    <div class="product">
                        <div class="image">
                            <a href="#"><img src=" <?= "images/wheels/wheelphotos/". $product["bigpic"]; ?>" alt= "<?= $product["manufacturer"]; ?>" class="img-responsive"></a>
                            <div class="quick-view-button"><button type="button" onclick="quickModal(<?= $product["recid"]; ?>)"  class="btn btn-default btn-sm">Quick view</button></div>
                        </div>
                        <div class="text">
                            <p class="brand"><a href="#"><?= $product["manufacturer"]; ?></a></p>
                            <h3> <a href="detail.php"><?= $product["diam"]; ?></a></h3>
                            <p class="price">$<?= $product["rrp"]; ?></p>
                            <button class="btn btn-default btn-sm btn-primary" href="detail.php">Details</button>
                        </div>
                    </div>
                </div>

                <?php endwhile; ?>
            </div>
            <?php } ?>

Answer 1

您的JPanel graphicsPanel = new JPanel(); int incorrectGuesses =0; @Override public void paintComponent(Graphics g){ super.paintComponent(g); Graphics2D g2D = (Graphics2D) g; BasicStroke aStroke = new BasicStroke(15.0f, BasicStroke.CAP_ROUND, BasicStroke.JOIN_ROUND); g2D.setStroke(aStroke); g2D.setColor(Color.BLUE); switch (incorrectGuesses) { case 10: g2D.drawLine(200, 200, 150, 250); // Left leg case 9: g2D.drawLine(200, 200, 250, 250); // Right leg case 8: g2D.drawLine(150, 150, 200, 175); // Left arm case 7: g2D.drawLine(250, 150, 200, 175); // Right arm case 6: g2D.drawLine(200, 200, 200, 150); // Torso case 5: g2D.drawOval(175, 100, 50, 50); // Head case 4: g2D.drawLine(200, 100, 200, 50);// Noose case 3: g2D.drawLine(200, 50, 100, 50);//Plank case 2: g2D.drawLine(100, 300, 100, 50); //Post case 1: g2D.drawLine(20, 300, 300, 300); //Stage } repaint(); graphicsPanel.add(new HangmanGraphics()); }循环将运行与您选择的查询一样多的记录。如果你需要在一定数量的记录之后退出该循环，你可以使用一个变量来计算你完成循环的次数，然后{while}循环中的while。您的break循环将完成下一次迭代并打印“row”div，for循环将处理下一对记录，直到您再次while。

PHP For循环不产生输出

1 个答案: