在名为＆＃34;名称＆＃34;的列下我有一行持有价值＆＃34; Joe＆＃34;。
当我搜索＆＃34; Joe Bloggs＆＃34;时，我可以使用什么？它将返回仅包含＆＃34; Joe＆＃34;？
的行答案 0 :(得分：2)
你可以这样做：
:value其中void delete(String name) {
path = jEdit.getSettingsDirectory()+"/"+name;
VFS vfs = VFSManager.getVFSForPath(path);
session = vfs.createVFSSession(path,view);
vfs._delete(session, path, view);
if (session != null) vfs._endVFSSession(session,view);
}
runInSystemShell(view, "cd " + jEdit.getSettingsDirectory());
// clean up files
delete("abbrevs"); // I use SuperAbbrevs
delete("killring.xml");
delete("recent.xml");
delete("perspective.xml");
delete("activity.log");
delete("history");
delete("printspec");
delete("registers.xml");
delete("pluginMgr-Cached.xml.gz");
delete("macros" + File.separator + ".macroManagerCache"); // File.separator = System.getProperty("file.separator")
delete("server");
delete("jedit_quicknote.txt"); // or qn.txt
delete("mirrorList.xml"); // mirrorList can be updated by Options -> Plugin Manager
// clean up directories
delete("jars-cache");
delete("settings-backup");
delete("cache");
delete("DockableWindowManager");
delete("PluginManager.download");
delete("printspec");
runInSystemShell(view, "rm -f ~/Google\\ Drive/doc/jedit.zip; zip -r ~/Google\\ Drive/doc/jedit.zip * -x '*.DS_Store'");
应该是您将绑定到该SQL语句的参数。
答案 1 :(得分：0)
您还可以使用LIKE：
select *
from t
where $value like concat('%', name, '%');
如果您只想在开头使用“Joe”这个名字：
select *
from t
where $value like concat(name, '%');