我在使用C编写BST时遇到问题。我一直遇到分段错误错误。我认为问题源于insertNode函数。我在函数中添加了printf()语句,并在函数调用之后直接查看是否添加了newNode。请忽略其余的代码,因为它没有完成,只是试图让insertNode函数起作用。
#include <stdio.h>
#include <stdlib.h>
//structure for node
struct btNode {
int data;
struct btNode *left;
struct btNode *right;
};
//prototypes
struct btNode* createNode(int x);
void insertNode(struct btNode *tree, struct btNode *root);
int main(){
int x,n=-1,i=0; //local variables
struct btNode *head=NULL;
while (n <= 0){
printf("Enter the number of nodes in the Tree(>0): ");
scanf("%i", &n);
}
while(i < n){
printf("Enter an integer: ");
scanf("%i", &x);
struct btNode *newNode=createNode(x);
insertNode(head,newNode);
printf("%d",head->data); //breaks program here????
i++;
}
while (x < 0){
printf("Enter a integer from 0-5: ");
scanf("%i",&x);
if (x == 0){
printf("Program Exit.\n");
exit(0);
}else if(x==1){
}else if(x==2){
}else if(x==3){
}else if (x==4){
}else if(x==5){
}
x=-1;
}
return 0;
}
//creates and returns a pointer to a new node
struct btNode* createNode(int x)
{
struct btNode *newNode;
newNode=(struct btNode*)malloc(sizeof(struct btNode));
if (newNode == NULL){
printf("Memory Allocation Failed./n");
exit(20);
}else{
newNode->data=x;
newNode->left=NULL;
newNode->right=NULL;
return newNode;
}
}
void insertNode(struct btNode *tree, struct btNode *newNode){
if (tree==NULL){
tree=newNode;
printf("%d",tree->data); //works fine here!
}else if(tree->data <= newNode->data){
insertNode(tree->right, newNode);
}else if(tree->data > newNode->data){
insertNode(tree->left, newNode);
}
}
答案 0 :(得分:1)
将node
插入树结构后,必须返回struct btNode *insertNode(struct btNode *tree, struct btNode *newNode){
if (tree==NULL){
tree=newNode;
printf("%d", tree->data); //works fine here!
return tree;
}else if(tree->data <= newNode->data){
tree->right = insertNode(tree->right, newNode);
return tree;
}else if(tree->data > newNode->data){
tree->left = insertNode(tree->left, newNode);
return tree;
}
}
。所以你的正确功能是:
head = insertNode(head, newNode);
同时修改你的电话:
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