我想获取两个数组collected = [1, 0, 2,]
和teacher = ['Zimmerman', 'Tischler', 'Johnson']
的内容,并使用sort()
方法在表中显示这些数组。所以这看起来像这样:
约翰逊 - 2
齐默尔曼 - 1
Tischler - 0
有人知道怎么做吗?
答案 0 :(得分:0)
您可以使用按collected
排序并使用indexOf
功能
参见工作示例:
var collected = [1, 0, 2];
var teacher = ['Zimmerman', 'Tischler', 'Johnson'];
var res = collected.slice().sort((a, b) => b - a)
.map(e => `<tr><td>${teacher[collected.indexOf(e)]}</td> <td>${e}</td></tr>`).join('');
document.write('<table>' + res + '</table>' );
答案 1 :(得分:0)
完整示例:
<table id="tab" border="1">
</table>
<script type="text/javascript">
var
collected,
teacher,
table,
data = '',
source = [];
collected = [1, 0, 2,];
teacher = ['Zimmerman', 'Tischler', 'Johnson'];
for (var i in collected) {
source.push([collected[i], teacher[i]]);
}
source.sort(function(a, b) {
return a[0] < b[0];
});
table = document.getElementById('tab');
for (var i in source) {
data += '<tr><td>' + source[i][0] + '</td><td>' + source[i][1] + '</td></tr>';
}
table.innerHTML = data;
</script>
结果:
答案 2 :(得分:0)
您可以对索引进行排序,并将该数组用于以后的内容组合。
var collected = [1, 0, 2, ],
teacher = ['Zimmerman', 'Tischler', 'Johnson'],
cIndices = collected.map(function (_, i) { return i; }),
table = document.createElement('table');
cIndices.sort(function (a, b) {
return collected[b] - collected[a];
});
cIndices.forEach(function (a) {
function getTD(s) {
var td = document.createElement('td');
td.innerHTML = s;
return td;
}
var tr = document.createElement('tr');
tr.appendChild(getTD(teacher[a]));
tr.appendChild(getTD(collected[a]));
table.appendChild(tr);
});
document.body.appendChild(table);
答案 3 :(得分:0)
使用result
作为业务逻辑,使用html
作为演示文稿。一个合适的方法:
var collected = [1, 0, 2],
teacher = ['Zimmerman', 'Tischler', 'Johnson'],
result = {},
html = '';
// business logic
collected.forEach(function (e, i) {
result[e] = teacher[i];
});
// presentation
Object.keys(result)
.sort()
.reverse()
.forEach(function (e) {
html += '<tr><td>' + result[e] + '</td>';
html += '<td>' + e + '</td></tr>';
});
document.write('<table>' + html + '</table>');
&#13;