Question

在java应用程序中，我们通过使用de below代码从REST获得响应。

String response = performPostCall(wmeAPI.vote("" + rowItem.getPoll_id()), has);

在swift中，我正在使用Alamofire

进行发布通话

我打了电话

Alamofire.request(.POST, url, parameters: parameters, encoding:.JSON).responseString
            { response in switch response.result {
                case .Success(let JSON):
                    print("Success \(JSON)")
                case .Failure(let error):
                    print("Request failed with error: \(error)")
                    }
        }

如何从此帖后调用中获取响应字符串。

Answer 1

您需要使用响应JSON

所以，将responseString更改为responseJSON

例如：

Alamofire.request(.GET, "YOUR_URL").responseJSON { (responseData) -> Void in
    if((responseData.result.value) != nil) {
        let swiftyJsonVar = JSON(responseData.result.value!)
        print(swiftyJsonVar)
    }
}

对于POST电话：

Alamofire.request(.POST, "YOUR_URL", parameters: nil, encoding: ParameterEncoding.JSON, headers: nil).responseJSON { (responseObject) -> Void in

    print(responseObject)

    if responseObject.result.isSuccess {
        let resJson = JSON(responseObject.result.value!)
        print(resJson)
    }
    if responseObject.result.isFailure {
        let error : NSError = responseObject.result.error!
        print(error)
    }
}

Answer 2

如果你检查Alamofire Doc。，已经定义了如何获得响应的信息String以及如何获得响应JSON

响应JSON处理程序

 Alamofire.request(.GET, "https://httpbin.org/get")
     .responseJSON { response in
         debugPrint(response)
     }

响应字符串处理程序

 Alamofire.request(.GET, "https://httpbin.org/get")
     .responseString { response in
         print("Success: \(response.result.isSuccess)")
         print("Response String: \(response.result.value)")
     }

链式响应处理程序

   Alamofire.request(.GET, "https://httpbin.org/get")
     .responseString { response in
         print("Response String: \(response.result.value)")
     }
     .responseJSON { response in
         print("Response JSON: \(response.result.value)")
     }

参考Alamofire Usage

阅读来自Json Post Call Swift的回复

2 个答案: