Question

有人可以告诉我如何让这个代码在按下4时返回主菜单。我知道我必须做while循环，但我不知道如何。现在我退出作为返回，所以它关闭整个程序，但我希望它返回主菜单并重新启动eventSelection。

import java.util.*;
public class SchedulingProgram
 {
  public static void main (String [] args)
   {
    eventSelection();
   }
  public static void eventSelection()
{
Scanner sc = new Scanner(System.in);
System.out.println("Select Scheduling Action");
System.out.print("Add and Event = 1. \nDisplay Events = 2. \nPrint Alert = 3. \nExit = 4. \nINPUT : ");
int actionSelect = sc.nextInt();

if (actionSelect >= 1 && actionSelect <= 4)
 {
 if (actionSelect == 1)
  {
   addEvent();
  }
 else if (actionSelect == 2)
  {
   displayEvent();
  }
 else if (actionSelect == 3)
  {
   printAlert();
  }
 else if (actionSelect == 4)
  {
   return;
  }
 }
else
 {
  System.out.println("Error : Choice " + actionSelect + " Does Not Exist.");
 }
}

Answer 1

你可以使用这样的无限循环来执行此操作，但是用户将无法完全退出程序，如果要命令退出程序，则可以在该命令中使用public static void eventSelection() { while (true){ Scanner sc = new Scanner(System.in); System.out.println("Select Scheduling Action"); System.out.print("Add and Event = 1. \nDisplay Events = 2. \nPrint Alert = 3. \nExit = 4. \nINPUT : "); int actionSelect = sc.nextInt(); if (actionSelect >= 1 && actionSelect <= 4) { if (actionSelect == 1) { addEvent(); } else if (actionSelect == 2) { displayEvent(); } else if (actionSelect == 3) { printAlert(); } else if (actionSelect == 4) { System.out.println("Returning to selection menu");// Do nothing, next loop will be executed } } else { System.out.println("Error : Choice " + actionSelect + " Does Not Exist."); } }。

On Error GoTo ErrorHandler

}

Answer 2

从eventSelection（）返回一些值。检查main函数返回的值。如果它与你的值匹配，则再次调用eventSelection（）

如何让退出让我回到主菜单（Java）

2 个答案: