Question

我有以下文字：

<Data>
    <xpath>/Temporary/EIC/SpouseSSNDisqualification</xpath>
    <Gist>AllConditionsTrue</Gist>
    <Template>
        <Text id="1">Your spouse is required to have a Social Security number instead of an ITIN to claim this credit.  This is based on the IRS rules for claiming the Earned Income Credit.</Text>
    </Template>
</Data>
<Data>
    <xpath>/Temporary/EIC/SpouseSSNDisqualification</xpath>
    <Gist>AllConditionsTrue</Gist>
    <Template>
        <Text id="1">Your spouse has the required Social Security number instead of an ITIN to claim this credit.  This is based on the IRS rules for claiming the Earned Income Credit.</Text>
    </Template>
</Data>

我想在xpath标签之间提取数据，而不是标签本身。

输出应为：

/Temporary/EIC/SpouseSSNDisqualification

这个正则表达式似乎给了我所有的文字，包括我不想要的xpath标签：

<NodeID>(.+?)<\/NodeID>

修改

这是我的Java代码，但我不确定这是否会增加我的问题的价值：

    try {
        String xml = FileUtils.readFileToString(file);
        Pattern p = Pattern.compile("<xpath>(.+?)<\\/xpath>");
        Matcher m = p.matcher(xml);

        while(m.find()) {
            System.out.println(m.group(0));
        }
    }

Answer 1

易。这是因为你取得了所有的结果，而不仅仅是第1组的价值。

String nodestr = "<xpath>/Temporary/EIC/SpouseSSNDisqualification</xpath>";
String regex = "<xpath>(.+?)<\/xpath>";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(nodestr);
if (matcher.matches()) {
    String tag_value = matcher.group(1); //taking only group 1
    System.out.println(tag_value); //printing only group 1
}

Answer 2

您可以尝试使用前瞻和后视方法：

Pattern pattern = Pattern.compile("(?<=<xpath>)(.*?)(?=</xpath>)");
Matcher matcher = pattern.matcher(str);
while (matcher.find()) {
    String group = matcher.group();
    System.out.println(group);
}

我认为这是一种更清洁的方式。

正则表达式用于在标签之间提取文本而不是标签

2 个答案: