当我提交表单时,我已成功将我的网站连接到我的数据库,但没有任何内容插入到数据库中。
以下代码:
<?php
if( $_POST )
{
$con = mysql_connect("server","user","pass");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("buycruisesdb", $con);
$users_name = $_POST['name'];
$users_email = $_POST['email'];
$users_name = mysql_real_escape_string($users_name);
$users_email = mysql_real_escape_string($users_email);
$query = "
INSERT INTO `website_subscribers`(`name_sub`, `email_sub`) VALUES ([$users_name],[$users_email])";
mysql_query($query);
echo "<h2>Thank you for subscribing!</h2>";
echo $query;
echo $users_name;
echo $users_email;
mysql_close($con);
}
?>
buycruisesdb =数据库
website_subscribers =数据库内的表
name_sub / email_sub =表格内的列
表单html如下:
!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
</head>
<body>
<form action="php/subscriber.php" id="form" method="post" name="form">
<input id="name_sub" name="name" placeholder="Name" type="text">
<input id="email_sub" name="email" placeholder="Email" type="text">
<input type="submit" value="Submit" name="f_submit">
</form>
</body>
</html>
不确定为什么这不输入任何人有想法?
它说它正在插入适当的值并进入适当的表 Image
答案 0 :(得分:1)
方括号在MySQL查询中无效。你应该在字符串周围使用引号。
$query = "INSERT INTO `website_subscribers` (`name_sub`, `email_sub`) VALUES ('$users_name', '$users_email')";
答案 1 :(得分:1)
将其更改为:
$query = "
INSERT INTO website_subscribers (name_sub,email_sub) VALUES ('".$users_name."','".$users_email."') ";
&#13;
只需复制代码并试用即可