Question

我需要从文件中获取一个字符串，在起始字符串和结束字符串之间，但是在返回的字符串中，我需要在起始字符串之前有2行。

例如，下面是我的字符串块，我需要找到以“：25：RO68BTRL04701202281399XX”开头并以“ - }”开头的行，但还要在开始搜索字符串之前返回前两行：< / p>

{1:F01BTRLRO22AXXX1111111111}{2:I940BTRLRO22XXXXN}{3:{108:047MSOG16103001F}}{4: <br />
:20:047RONCRT0028139901<br />
:25:RO68BTRL04701202281399XX<br />
:28C:00697/00001<br />
:60F:C160411RON580868,35<br />
:61:1604110411C537,91NTRFC31EIOP161020001<br />
:86:PLATI CARTELE  AP 1351271   CALGIRA  FCT.12138114 S I FCT.12145656 CALGIRA TR ANSILVANIA SRL RO81BTRL RO NCRT0278617701 36 BTRL RO2 2 Incasare OP   canal ele ctronic<br />
:61:1604110411C279,44NTRF801EIOP161020101
:86:12135020 12144465 AP11309 84 FANTASI STILL SRL FANT ASI STILL SRL RO56BTRL 001 01202N50350XX 16 BTRL RO22 Incasare OP   canal elec tronic<br />
:61:1604110411C1149,41NTRF020EIOP161020002<br />
:86:CV F 12143919 12135600 EN IGMA COM SRL RO08BTRL 0200 1202D01120XX 159 BTRL RO22 Incasare OP   canal elec tronic<br />
:61:1604110411C53,52NTRF325EIOP161020051<br />
:86: AP1383577 cv fact 1213519 0/ 31.03.20 16 reincarcari electronice GLISSANDO CO STEA SNC RO26BTRL 02501202 121834XX 20 BTRL RO22 Inca sare OP   canal electronic<br />
:61:1604110411D695,15NTRF047EPOP161020204<br />
:86:PLATA PP F 2479 PRAM CADE S SRL 7227 BTRL RO22 Plata OP intra   canal electronic<br />
:61:1604110411C223,01NTRF010EIOP161020085<br />
:86: AP 1353368 F 12134396 121 40760 COM TURISM MARKET S RL Comturism Market SRL C OMTURISM MARKET SRL RO21B TRL01001202M68296XX 94 BT RLRO22 Incasare OP   cana l electronic<br />
:62F:C160411RON1162675,04 <br />
:64:C160411RON1162675,04 <br />
-}

我在java中的代码是这样的（正在运行，只是它没有返回我想要的东西，意思是startString减去2行和endString之间的字符串）：

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;

public class bt {
	public static void main(String[] args) {
	    // TODO code application logic here
	    File fileName = new File("bta.txt");
	    
	    try {
	        String startToken = ":25:RO68BTRL04701202281399XX";
	        String endToken = "-}";
	        boolean output = false;
			
			int nrLinie=0;
	
	        Scanner scan = new Scanner(fileName);
	        while (scan.hasNextLine()) {
	            String line = scan.nextLine();
	            
	            if (output==false && line.indexOf(startToken) > -1) {
	                output = true;
	                //line = line.substring(line.indexOf(startToken)+startToken.length());
	                line = line.substring(line.indexOf(startToken)+1,line.indexOf(endToken)+endToken.length());
	            } else if (output && line.indexOf(endToken) > -1) {
	                //output = false;
	                //System.out.println(line.substring(0, line.indexOf(endToken)));
	            }
	            
	            if (output) {
	                System.out.println(line);
	            }
	        }
	    } catch (FileNotFoundException e) {
	        e.printStackTrace();
	    }
	}
}

谢谢你，因为任何帮助都非常感激。

Answer 1

这个正则表达式可以做到。请参阅regex101 for demo。

((?:[^\r\n]*\r?\n){2}):25:RO68BTRL04701202281399XX(.*?)-\}

在java中的两个字符串之间获取字符串，之前开始两行

1 个答案: