Question

我一直在玩java中的selenium，我遇到了一个我无法弄清楚的问题。

在此页面上：http://www.legalcontracts.com/contracts/lease-agreement-form/?ldcn=menu+name

从第三页（地址页面）到第四页我可以设置地址：

@FindBy(xpath="//div[@class=' qd spropertyAddress']/div[@class='ans']/input")
    private WebElement address;

public void SetAddress(String addressName){
        address.sendKeys(addressName);
    }

但是当我尝试继续

时

@FindBy(xpath="//a[contains(text(),'Continue')]")
    private WebElement continuebutton;
continuebutton.click();

我得到org.openqa.selenium.ElementNotVisibleException。 “继续”按钮与上一页的标识@FindBy相同，因此我不确定是否与此有关。我尝试了许多不同的方法来尝试处理这个问题，但似乎唯一有效的方法是thread.sleep，这不是处理这个问题的好方法。

我尝试过的事情：

WebDriverWait wait = new WebDriverWait(driver,30);
        wait.until(ExpectedConditions.elementToBeClickable(continuebutton));
        wait.until(ExpectedConditions.elementToBeClickable(continuebutton));
        wait.until(ExpectedConditions.presenceOfElementLocated((By) continuebutton));
        wait.until(ExpectedConditions.visibilityOfElementLocated((By) continuebutton));


public void waitForJQuery(WebDriver driver) {
    (new WebDriverWait(driver, 10)).until(new ExpectedCondition<Boolean>() {
        public Boolean apply(WebDriver d) {
            JavascriptExecutor js = (JavascriptExecutor) d;
            return (Boolean) js.executeScript("return !!window.jQuery && window.jQuery.active == 0");
        }
    });
}

public void waitForJavaScript(WebDriver driver){
    (new WebDriverWait(driver, 10)).until(new ExpectedCondition<Boolean>() {
        public Boolean apply(WebDriver driver) {
            return ((JavascriptExecutor)driver).executeScript("return document.readyState").equals("complete");
        }
    }
);

public void checkPageIsReady(WebDriver driver) { JavascriptExecutor js = (JavascriptExecutor)driver; //Initially bellow given if condition will check ready state of page. 

    if (js.executeScript("return document.readyState").toString().equals("complete")){ 
        System.out.println("Page Is loaded."); 
        return; 
        } 

    //This loop will rotate for 25 times to check If page Is ready after every 1 second. 
    //You can replace your value with 25 If you wants to Increase or decrease wait time. 
    for (int i=0; i<25; i++){ 
        try { 
            Thread.sleep(1000); }
        catch (InterruptedException e) {} 

        //To check page ready state. 
        if (js.executeScript("return document.readyState").toString().equals("complete")){ 
            break; } } 
    }

我从上一页继续使用相同的继续，但是在不同的页面对象中：

@FindBy(xpath="//a[contains(text(),'Continue')]")
    private WebElement continuebutton;
continuebutton.click();

selenium会将当前的继续按钮与前一个按钮混淆吗？

Answer 1

使用以下代码：

driver.findElement(By.cssSelector("div.ans>input#ctl00_Content_ctrlQuestions_ctl194_ctl21_ctl06_ctl01_ctl01_ctl01_in")).click();

driver.findElement(By.cssSelector("div.ans>input#ctl00_Content_ctrlQuestions_ctl194_ctl21_ctl06_ctl01_ctl01_ctl01_in")).clear();

driver.findElement(By.cssSelector("div.ans>input#ctl00_Content_ctrlQuestions_ctl194_ctl21_ctl06_ctl01_ctl01_ctl01_in")).sendKeys("ur address");

Thread.sleep(2000);

//click on continue button

driver.findElement(By.cssSelector("  .largeProceedButton.continueButtonnContinueFirst.nContinue")).click();

使用cssSelector而不是上面提到的xpath点击“继续”按钮。

org.openqa.selenium.ElementNotVisibleException点击继续按钮

1 个答案: