Question

如何合并2个（结构相同的）JSON对象（在Google电子表格脚本中）？

{"records":[{"id":28100988,"work_text_reviews_count":13,"average_rating":"3.10"},{"id":10280687,"work_text_reviews_count":80,"average_rating":"3.87"}]}

{"records":[{"id":16135639,"work_text_reviews_count":0,"average_rating":"0.00"},{"id":17978337,"work_text_reviews_count":2414,"average_rating":"3.76"{"id":360721218,"work_text_reviews_count":4924,"average_rating":"3.98"}]}

合并后，结果应为：

{"records":[{"id":28100988,"work_text_reviews_count":13,"average_rating":"3.10"},{"id":10280687,"work_text_reviews_count":80,"average_rating":"3.87"},{"id":16135639,"work_text_reviews_count":0,"average_rating":"0.00"},{"id":360721218,"work_text_reviews_count":4924,"average_rating":"3.98"}]}

因为在Google Spreadsheets中我不能使用JQuery，而且我花了一整天时间尝试使用javascript解决方案，这些解决方案无法正常运行。

Answer 1

您可以使用concat：

var json1 = {
  "records": [{
    "id": 28100988,
    "work_text_reviews_count": 13,
    "average_rating": "3.10"
  }, {
    "id": 10280687,
    "work_text_reviews_count": 80,
    "average_rating": "3.87"
  }]
}

var json2 = {
  "records": [{
    "id": 16135639,
    "work_text_reviews_count": 0,
    "average_rating": "0.00"
  }, {
    "id": 17978337,
    "work_text_reviews_count": 2414,
    "average_rating": "3.76"
  }, {
    "id": 360721218,
    "work_text_reviews_count": 4924,
    "average_rating": "3.98"
  }]
}


var json3 = json1.records.concat(json2.records);

在GAS中合并2个JSON对象（无jquery）

1 个答案: