Question

我有一个允许用户由非用户发送消息的表单，脚本获取表单内容，将其存储在我的messages表中，然后最终通过电子邮件将用户的内容发送到他们的电子邮件地址。

我无法弄清楚为什么我的表单不会提交并返回错误消息，因为我没有正确完成。没有发送电子邮件，也没有在数据库表中输入任何内容。

我的表单代码;

<form class="signup-form" action="sendmail.php" id="email_submit" method="POST">
<fieldset>
<input type="text" name="msg_touserid" id="msg_touserid" value="<?php echo htmlentities($_GET["uid"], ENT_QUOTES, 'UTF-8'); ?>" style="display: none;">
<input type="text" name="msg_tousername" id="msg_tousername" value="<?php echo htmlentities($_GET["username"], ENT_QUOTES, 'UTF-8'); ?>" style="display: none;">
<input type="text" placeholder="Your name..." name="msg_fromname" id="msg_fromname" value=""><br />
<input type="text" placeholder="Your mobile number..." name="msg_mobile" id="msg_mobile" value=""><br />
<input type="email" name="msg_toemail" id="msg_toemail" value="XXX@gmail.com" style="display: none;">

<input type="email" placeholder="Your email..." name="msg_fromemail" id="msg_fromemail" value=""><br />
<input type="text" placeholder="Message subject..." name="msg_subject" id="msg_subject" value=""><br />
<textarea name="msg_messagebody" id="msg_messagebody" style="height: 282px; background-image: none; background-position: 0px 50%; background-repeat: repeat;"></textarea>
</fieldset>
<input type="submit" class="btn-colored submit-send-email" value="Send email" />
</form>

我的sendmail.php代码;

$connection = mysql_connect('localhost', 'XXX', 'XXX');
    if (!$connection){
        die('Could not connect: ' . mysql_error());
    }

    mysql_select_db( 'DB' );
    if (isset($_POST['email_submit'])){
        $msg_touserid = $_POST['msg_touserid'];
        $msg_tousername = $_POST['msg_tousername'];
        $msg_fromname = $_POST['msg_fromname'];
        $msg_mobile = $_POST['msg_mobile'];
        $msg_toemail = $_POST['msg_toemail'];
        $msg_fromemail = $_POST['msg_fromemail'];
        $msg_subject = $_POST['msg_subject'];
        $msg_messagebody = $_POST['msg_messagebody'];

        $sql = "INSERT INTO messages (msg_touserid, msg_tousername, msg_fromname, msg_mobile, msg_toemail, msg_fromemail, msg_subject, msg_messagebody) 
                VALUES ('$msg_touserid', $msg_tousername', '$msg_fromname', '$msg_mobile', '$msg_toemail', '$msg_fromemail', '$msg_subject', '$msg_messagebody')";
        if (!mysql_query($sql,$connection)){
            die('Error: ' . mysql_error());
        }

        $emailID = "$msg_toemail";
        $subject = "Enquiry from. $msg_fromname . through our website";
$body = <<<EOD

        <table cellspacing="0" cellpadding="1" border="1">
            <tbody>
                <tr>
                    <td style="padding: 5px 10px;" width="150">Name: </td>
                    <td style="padding: 5px 10px;">$msg_fromname</td>
                </tr>
                <tr>
                    <td style="padding: 5px 10px;" width="150">Mobile: </td>
                    <td style="padding: 5px 10px;">$msg_mobile</td>
                </tr>
                <tr>
                    <td style="padding: 5px 10px;" width="150">Email: </td>
                    <td style="padding: 5px 10px;">$msg_fromemail</td>
                </tr>
                <tr>
                    <td style="padding: 5px 10px;" width="150">Message: </td>
                    <td style="padding: 5px 10px;">$msg_messagebody</td>
                </tr>
            </tbody>
        </table>

EOD;

        $headers = "From: admin@domain.com\r\n";
        $headers .= "MIME-Version: 1.0\r\n";
        $headers .= "Content-Type: text/html; charset=\"iso-8859-1\"\n";
        $headers .= "X-Priority: 1\r\n";
        $headers .= "X-MSMail-Priority: High\n";
        $headers .= "X-Mailer: PHP". phpversion() ."\r\n";

        mail($emailID, $subject, $body, $headers );
        echo "<h4>Thank you for your message.</h4>";

    } else {
        echo("Oops... Please check you have completed the form correctly.");
    };

我的数据库结构;

id                      int(10) (AI)
msg_touserid            int(10) 
msg_tousername          varchar(100)
msg_fromname            varchar(100)
msg_mobile              varchar(20)
msg_toemail             varchar(100)
msg_fromemail           varchar(100)    
msg_subject             varchar(200)
msg_messagebody         varchar(1000)   
msg_sent                timestamp

Answer 1

提交按钮没有name属性。

<input type="submit" class="btn-colored submit-send-email" value="Send email" />

所以，条件

if (isset($_POST['email_submit'])){

不满意。

<强>解决方案：

添加name以提交按钮。

更正后的代码：

<input type="submit" class="btn-colored submit-send-email" value="Send email" name="email_submit" />

Answer 2

它没有提交/发送电子邮件，因为它从来没有机会。

if (isset($_POST['email_submit'])){

永远不会满足，因为email_submit未在您的表单中定义。您已将其设置为表单ID <form id="email_submit">，但ID不会以与$_POST相同的方式传递给name。

在表单中提交名称为email_submit的提交按钮：

<input name="email_submit" type="submit" class="btn-colored submit-send-email" value="Send email">

现在初始条件将满足。

发送电子邮件并写入数据库不起作用

2 个答案: