Question

我的数据就像这样。

+------------+----------------+--------+-------+
| date       | shop_id        | status | count |
+------------+----------------+--------+-------+
| 2016-04-01 | 121101201      | A      |     9 |
| 2016-04-01 | 121101201      | B      |     6 |
| 2016-04-04 | 121101201      | A      |     4 |
| 2016-04-04 | 121101201      | B      |     5 |
| 2016-04-05 | 121101201      | A      |    11 |
| 2016-04-05 | 121101201      | B      |     3 |

我想进行查询并像这样返回。

+------------+----------------+----------+----------+
| date       | shop_id        | status=A | status=B |
+------------+----------------+----------+----------+
| 2016-04-01 | 121101201      | 9        |        6 |
| 2016-04-04 | 121101201      | 4        |        5 |
| 2016-04-05 | 121101201      | 11       |        3 |

如何为上述输出进行sql查询。

感谢您的帮助和分享。

Answer 1

SELECT  date, 
        shop_id, 
        SUM(case when status='A' then count else 0 end) AS `status=A`,
        SUM(case when status='B' then count else 0 end) AS `status=B`
FROM table_name
GROUP BY date, shop_id 
ORDER BY date desc

Answer 2

您可以使用条件聚合执行此操作：

SELECT  `date`, shop_id, 
        SUM(status='A') AS `status=A`,
        SUM(status='B') AS `status=B`
FROM mytable
GROUP BY `date`, shop_id

MySQL查询 - 如何制作此示例报告？

2 个答案: