Question

使用以下代码，我创建了两种类型的节点。在Neo4J

  public async Task CreateData()
  {
     AddNodesAsync<Companies>(myCompanies);
     AddNodesAsync<Employess>(myEmployes);
  }

  public Task AddNodesAsync<T>(List<T> nodes)
    {
        return client
            .Cypher
            .Create("(n:" + typeof(T).Name + " {nodes})")
            .WithParams(new {nodes})
            .ExecuteWithoutResultsAsync();
    }

每个员工都有公司ID。现在，当员工公司的ID与公司的ID匹配时，我希望将所有这些联系起来。

使用以下代码，我可以将一个员工与一个公司

相关联

await client.Cypher
            .Match("(company:Company)", "(employee:Employee)")
            .Where((employee: company) => employee.ComanyId == company.Id)                       
            .Create("employee-[:BELONGS_TO]->company")
            .ExecuteWithoutResultsAsync();

但我怎么能告诉它应该将这个id ref雇用的所有人都链接到他们的对应公司？

Answer 1

我认为某处存在拼写错误，这是我使用的代码，它会按照您的说法生成链接。

将这些用作POCO：

public class Company {
    public int Id { get; set; }
}

public class Employee {
    public int Id { get; set;}
    public int CompanyId { get; set;}
}

添加它们：

var companies = new List<Company> { new Company { Id = 1 }, new Company {  Id = 2 } };
var employees = new List<Employee>
{
    new Employee{ Id=1, CompanyId =1 },
    new Employee{ Id=2, CompanyId =1 },
    new Employee{ Id=3, CompanyId =1 },
    new Employee{ Id=4, CompanyId =2 },
    new Employee{ Id=5, CompanyId =2 },
};

await AddNodesAsync(companies);
await AddNodesAsync(employees);

下一位按预期生成图表，关系全部正确创建。

await client.Cypher
    .Match("(company:Company)","(employee:Employee)")
    .Where((Company company, Employee employee) => employee.CompanyId == company.Id)
    .Create("(employee)-[:BELONGS_TO]->(company)")
    .ExecuteWithoutResults();

通过ID链接两种类型的所有节点

1 个答案: