Question

这是我的代码：

from __future__ import division
import nltk
import string
import re
import math
from nltk import bigrams

f = open('C:/Python27/brown_A1_half.txt', 'rU')
w = open('C:/Python27/brown_A1_half_Out.txt', 'w')

#to read whole file using read()

filecontents = f.read()
from nltk.tokenize import sent_tokenize
sent_tokenize_list = sent_tokenize(filecontents)
result = ''
new_sentences = ["Start " + sentence + " End " for sentence in sent_tokenize_list]
result = ''.join(new_sentences)

tokens = nltk.word_tokenize(result)
#print tokens
bi_tokens = tuple(nltk.bigrams(tokens))
#print bi_tokens
bi_freq = nltk.FreqDist(bi_tokens)
for k, v in bi_freq.items():
print k, v

此结果bigram和value(=its frequency")。

如何在for循环中添加所有值？这意味着，v1 + v2 + v3 ... vn。我无法使用sum功能。

Answer 1

如果v只是一个数字，您可以sum bi_freq中sum(bi_freq.itervalues())所有的值：

bi_freq.itervalues()

bi_freq将获取sum的所有值，然后public $validate = array( 'attachmenturl' => array( 'rule' => array( 'extension', array('pdf', 'jpeg', 'jpg') ), 'message' => 'Please supply a valid image.' ) );将相互添加这些值。

Answer 2

我假设v是列表结构。

v = [1,2,3,4,5,6,7,8,9,10]

result = 0 
for items in v:
    result += items

print(result)

打印“55”

Answer 3

用这个替换你的最后两行：

v_sum = 0
for k, v in bi_freq.items():
    v_sum += v
    print k, v

如何添加“for clause”产生的所有值？

3 个答案: