是否可以组合使用以下结构嵌套的Reducer:
import 'user' from ...
import 'organisation' from ...
import 'auth' from ...
// ...
export default combineReducers({
auth: {
combineReducers({
user,
organisation,
}),
auth,
},
posts,
pages,
widgets,
// .. more state here
});
州有结构:
{
auth: {
user: {
firstName: 'Foo',
lastName: 'bar',
}
organisation: {
name: 'Foo Bar Co.'
phone: '1800-123-123',
},
token: 123123123,
cypher: '256',
someKey: 123,
}
}
auth
减速器具有以下结构:
{
token: 123123123,
cypher: '256',
someKey: 123,
}
所以也许扩散算子很方便? ...auth
不确定: - (
答案 0 :(得分:58)
使用keyStore = KeyStore.getInstance("AndroidKeyStore");
keyStore.load(null);
keyStore.aliases();
组合嵌套缩减器完全没问题。但是还有另一种非常方便的模式:嵌套的缩减器。
combineReducers
在上面的示例中,const initialState = {
user: null,
organisation: null,
token: null,
cypher: null,
someKey: null,
}
function authReducer(state = initialState, action) {
switch (action.type) {
case SET_ORGANISATION:
return {...state, organisation: organisationReducer(state.organisation, action)}
case SET_USER:
return {...state, user: userReducer(state.user, action)}
case SET_TOKEN:
return {...state, token: action.token}
default:
return state
}
}
可以将操作转发到authReducer
和organisationReducer
以更新其状态的某些部分。
答案 1 :(得分:36)
只是想详细说明@Florent给出的非常好的答案,并指出你也可以通过将减少器与减速器组合来实现嵌套减速器,从而有点不同地构建你的应用程序。 / p>
例如
// src/reducers/index.js
import { combineReducers } from "redux";
import auth from "./auth";
import posts from "./posts";
import pages from "./pages";
import widgets from "./widgets";
export default combineReducers({
auth,
posts,
pages,
widgets
});
// src/reducers/auth/index.js
// note src/reducers/auth is instead a directory
import { combineReducers } from "redux";
import organization from "./organization";
import user from "./user";
import security from "./security";
export default combineReducers({
user,
organization,
security
});
这假设状态结构略有不同。相反,像这样:
{
auth: {
user: {
firstName: 'Foo',
lastName: 'bar',
}
organisation: {
name: 'Foo Bar Co.'
phone: '1800-123-123',
},
security: {
token: 123123123,
cypher: '256',
someKey: 123
}
},
...
}
如果你无法改变状态结构,那么@ Florent的方法可能会更好
答案 2 :(得分:4)
受到@ florent's答案的启发,我发现你也可以试试这个。不一定比他的回答更好,但我认为它更优雅。
function userReducer(state={}, action) {
switch (action.type) {
case SET_USERNAME:
state.name = action.name;
return state;
default:
return state;
}
}
function authReducer(state = {
token: null,
cypher: null,
someKey: null,
}, action) {
switch (action.type) {
case SET_TOKEN:
return {...state, token: action.token}
default:
// note: since state doesn't have "user",
// so it will return undefined when you access it.
// this will allow you to use default value from actually reducer.
return {...state, user: userReducer(state.user, action)}
}
}
答案 3 :(得分:0)
示例(请参见下面的attachNestedReducers
)
import { attachNestedReducers } from './utils'
import { profileReducer } from './profile.reducer'
const initialState = { some: 'state' }
const userReducerFn = (state = initialState, action) => {
switch (action.type) {
default:
return state
}
}
export const userReducer = attachNestedReducers(userReducerFn, {
profile: profileReducer,
})
状态对象
{
some: 'state',
profile: { /* ... */ }
}
这是功能
export function attachNestedReducers(original, reducers) {
const nestedReducerKeys = Object.keys(reducers)
return function combination(state, action) {
const nextState = original(state, action)
let hasChanged = false
const nestedState = {}
for (let i = 0; i < nestedReducerKeys.length; i++) {
const key = nestedReducerKeys[i]
const reducer = reducers[key]
const previousStateForKey = nextState[key]
const nextStateForKey = reducer(previousStateForKey, action)
nestedState[key] = nextStateForKey
hasChanged = hasChanged || nextStateForKey !== previousStateForKey
}
return hasChanged ? Object.assign({}, nextState, nestedState) : nextState
}
}
答案 4 :(得分:0)
嵌套减速器示例:
import {combineReducers} from 'redux';
export default combineReducers({
[PATH_USER_STATE]: UserReducer,
[PATH_CART_STATE]: combineReducers({
[TOGGLE_CART_DROPDOWN_STATE]: CartDropdownVisibilityReducer,
[CART_ITEMS_STATE]: CartItemsUpdateReducer
})
});
输出:
{
cart: {toggleCartDropdown: {…}, cartItems: {…}}
user: {currentUser: null}
}