dynamic contacts = new List<dynamic>();
contacts.Add(new ExpandoObject());
contacts[0].Name = "Patrick Hines" ;
contacts[0].Phone = "206-555-0144" ;
想要做如下。
dynamic contacts = new List<dynamic>();
contacts.Add(new ExpandoObject());
contacts[0]. + "Name" = "Patrick Hines" ;
contacts[0]. + "Phone" = "206-555-0144" ;
答案 0 :(得分:0)
这个怎么样
var contacts = new List<Dictionary<string, string>>();
contacts.Add(new Dictionary<string, string>());
contacts[0]["Name"] = "Patrick Hines";
contacts[0]["Phone"] = "206-555-0144";
答案 1 :(得分:0)
如果您以ExpandoObject
的身份访问IDictionary<string, object>
,则可以按名称访问List<IDictionary<string, object>>
成员。将您的列表设为var contacts = new List<IDictionary<string, object>> { new ExpandoObject() };
contacts[0]["Name"] = "Patrick Hines";
var asDynamic = contacts as dynamic;
asDynamic[0].Phone = "206-555-0144";
,这样您就可以执行以下操作:
<fieldset id="field_1">
.....
<button class="action-button" id="button1" >Next</button>
</fieldset>
<fieldset id="field_2">
.....
<input type="button" name="previous" class="previous action-button" value="Previous" />
<button class="action-button" id="button2" >Next</button>
<button class="action-button" >Save&Exit</button>
</fieldset>
.....
<fieldset id="field_10">
.....
</fieldset>