我有一个像这样的实体类:
@NodeEntity
public class Patent {
@GraphId
private Long patentId;
private String patentName;
//2016-02-01
private String authorizedTime;
private String patentNumber;
@Fetch
@RelatedTo(type = "authorizedPerson")
private Set<Researcher> authorizedPersons = new HashSet<Researcher>();
private String createTime;
private String description;
我想得到这样的结果:
年总计
2013 6
2014 7
我尝试使用此Cypher查询:
match (n1:Patent)
with collect( DISTINCT subString(n1.authorizedTime,0,4)) as coll,subString(n1.authorizedTime,0,4) as val
return coll, reduce(s=0, val IN coll | s + 1) as numByY ;
但没有成功。
如何根据属性对属性进行分类?
非常感谢!
答案 0 :(得分:0)
此查询应每年返回该年份的节点数,按年份排序:
MATCH (n1:Patent)
RETURN LEFT(n1.authorizedTime, 4) AS year, COUNT(*) AS total
ORDER BY year;