Question

我们正在尝试执行Javadoc上的指令。到目前为止，我们有这个，但与索引参数混淆

 * Read the next run (or single character) and return the index of the symbol following the run (or symbol read).
   * Store the count and symbol for the run in the run parameter.
   * @param line - the input line being processed
   * @param index - the index of the first character in the next "run" (which might be just a single character)
   * @param run - where to store the symbol and count for the Run
   * @return the index of the symbol following the run just read
   */
  static int getNext(String line, int index, Run run) {
    line.charAt(index); //char first, something about a line
    return ?.symbol;//Store values
    run.count= ?.count; //the given number of that specific symbol or repetition
    enter code here
    run.symbol= ?.symbol; //whatever symbol you first see
    // TO BE COMPLETED

    return index+1;// just to make it advance so starter program doesn't loop infinitely
  }
}

Answer 1

这不是实际的RLE压缩函数，而是辅助函数，用于计算主RLE压缩函数正在处理的当前字符的重复。

这似乎需要做的是：

获取字符串index的索引line处的字符，并将其存储在Run对象的相应属性中。
对line后面的索引index中的字符进行迭代，直到遇到与您在开始时所采用的字符不相等的字符。
将找到的重复数量存储在Run对象的相应属性中。
返回遇到不相等字符的字符串中的位置。

这是我们的合作伙伴分配的运行长度编码程序。

1 个答案: