Question

Could anyone help me please.

I have created a function and within it I have an array containing string representations of integers.

var a = ['11', '22', '33' ,'44'];

What I am trying to do is to get a sum of individual digits in each element of the array. For example, the element containing '11' would give me 2 (1 + 1), '22' would give me 4 (2 + 2), and so on... So I should get [2,4,6,8] as the final output. How can I do this.

Thank you,

Answer 1

我假设你的意思是[2,4,6,8]作为输出，它是你提供的数组中每个元素的数字之和：

JsBin Example

staff

Answer 2

在数组上

map，拆分每个元素，将其转换为数字然后添加它们，然后返回最终数组。

function thing(arr) {
  return arr.map(function (el) {
    return el.split('').map(Number).reduce(function (p, c) {
      return p + c;
    });
  });
}

thing(arr) // [ 2, 4, 6, 8 ]

或者更糟糕的ES6：

const add = (a, b) => a + b;

function sumElements(arr) {
  return arr.map(el => [...el].map(Number).reduce(add));
}

DEMO

Answer 3

使用数学的另一种方法：

＆＃13;

var a = ['11', '22', '33' ,'44'];
var res = a.map(Number).map(function(digit) {
   var result = 0;
   while(digit) {
      result += digit % 10;
      digit = Math.floor(digit/10);
   }
   return result;
});

document.write(res);

＆＃13;

Answer 4

一张<div>

的班轮

ES6

Answer 5

这适用于所有浏览器：

JSON.Parse()

Answer 6

I'm not sure this is what you are asking, but I'll give it a go.

var a = [11,22,33,44];
var b = [];
for(i in a){
    b.push(a[i]*2);
}
//b == [22,44,66,88]

Your array is strings so you might want to wrap a[i] in the Number() function.

How do I sum up digits together within an Array

6 个答案: