Question

当我使用简单的for循环访问数组值时，索引变量会丢失，因此无法访问数组。使用索引号而不是变量可以工作但不可变。这是有史以来最烦人的代码。

/* jshint esnext: true, asi: true */
var neo4j = require('node-neo4j')


// Create the neo4J object
var db = new neo4j(serverURI)

exports.addPerson = (body, callback) => {

if (body.skills) {
    var sentSkills = body.skills
     var arraySkills = sentSkills.split(',')
}else {
    var sentSkills  = []
}

const sentName = body.name
const sentEmail = body.email
const sentUsername = body.username
const sentPassword = body.password
const lecturerStatus = body.lecturer

db.readNodesWithLabelsAndProperties('Person',{ email: sentEmail }, function (err, node) {
  if (err) {
    return console.log(err)
  }
  if (node.length > 0){
    // The user already exists
    callback({code:401,status:'failed',message:'Person already exsits with the name '+sentName,data:sentName})
  }
  else {
    // Insert new Person


    db.insertNode({
      name: sentName,
      email: sentEmail,
      skills: sentSkills,
      username: sentUsername,
      password: sentPassword,
      lecturer: lecturerStatus
  }, 'Person', function (err, node) {
    personNode = node
    if (err) {
      return console.log(err+1)
    }
    else {


     // I hate you for not working
     // The i = 0 variable is not accessible -> arraySkill[i]^.trim()
     // ERROR: cannot read property trim of undefined
      console.log("success")
      for (i = 0; i < arraySkills.length; i++){
        arraySkills = body.skills.split(',')
        db.cypherQuery("MATCH (s:Skill {name:'"+arraySkills[i].trim()+"'}) RETURN s", function(err, node){
          if (err){
            console.log("ERROR1")
            console.log(err)
          }
          else {
            console.log(arraySkills[0])
            if (node.data == '')
            {
              db.cypherQuery("CREATE (s:Skill {name:'"+arraySkills[i].trim()+"'}) RETURN s", function(err, node){
                if (err){
                  console.log("ERROR2")
                  console.log(err)
                }
                else {
                  console.log(node)
                   db.cypherQuery("MATCH (p:Person), (s:Skill) WHERE p.name = '"+sentName.trim()+"' AND s.name = '"+arraySkills[i].trim()+"' CREATE (p)-[r:knows]->(s) RETURN r", function(err, node){
                    if (err){
                      console.log("ERROR3")
                      console.log(err)
                    }
                    else { 
                      console.log(node)
                      console.log("Success")
                    }
                   })
                }
              })
            }
          }
        })   
      };

    }


      })



    // Output node data.
    callback({code:201,status:'success',message:'Person Added In '+sentName+' found...',data:node})

  }
})
}

Answer 1

这是一个关闭问题，修复它你必须将你的$ http调用移动到这样的新函数。

for (i = 0; i < arraySkills.length; i++){
   var skills = body.skills.split(',');
   dbQuery(skills,i); // In this function you have to write all the stuff you got under arraySkills = body.skills.split(',')

}

节点JS丢失了循环索引变量

1 个答案: