我正在编写一个需要将字符串验证为现有menuItem的类。理想情况下,我需要类似于MenuItemDisplayStr()的东西,但我需要它在运行时使用该函数而不是编译时间。是否有类似的东西可以检查字符串,如果它是一个menuItem?
感谢您的帮助!
答案 0 :(得分:2)
您必须迭代AOT并将字符串与菜单项进行比较。
此代码改编自此处提供的示例: https://blogs.msdn.microsoft.com/dsiebold/2010/08/13/use-x-to-loop-through-the-aot/
#AOT
//These are the macros for the paths found in #AOT.
//Don't use macros in practice. It's a bad habit.
//#define.MenuItemsDisplayPath('\\Menu Items\\Display')
//#define.MenuItemsOutputPath('\\Menu Items\\Output')
//#define.MenuItemsActionPath('\\Menu Items\\Action')
TreeNode menuItemParentNode;
//str menuItemName = "derp";//output: "derp is not a valid menu item"
str menuItemName = "ActivitiesMain";//output: "ActivitiesMain is a valid menu item"
//Only checking display here, you would need another level of
//nodes to do output and actions.
menuItemParentNode = TreeNode::findNode(#MenuItemsDisplayPath);
if (menuItemParentNode.AOTfindChild(menuItemName))
info(strFmt("%1 is a valid menu item", menuItemName));
else
info(strFmt("%1 is not a valid menu item", menuItemName));