我想按score_list的值class1排序{。}}。
我可以通过简单地对键进行排序来按字母顺序对score_list进行排序，但我无法弄清楚如何从数字到数字从最大到最小排序。
此外，我希望score_list仅存储最后3个输入，如果可能，我希望找到每个学生最后3个分数的平均值。
enter code here:
score_list = []
class1 = {}
what_class = input ("what class would you like?")
if what_class == ("1") :
print("class1 results")
student_name =input("name?")
score = input("score?")
choose = input("do you want to entre another student? y,n")
while choose == "y":
student_name =input("name?")
score = input("score?")
score_list.append(score)
choose = input("do you want to entre another score? y,n")
class1.setdefault(student_name,score_list)
if choose == "n":
sorted_names = sorted(class1.keys())
print(class1)
class1_items = class1.items()
print (type(class1_items))
for i in class1_items:
print (i)
如果有人可以帮助我，我会非常感谢它 谢谢你的帮助
[]更好地了解目标：1
enter code here
import heapq
from collections import deque
print("alphabetical(type:A),highest to lowest(type:B),Average(type:C)")
student_name = input("ENTER NAME")
result_type = input ("WHICH TYPE OF RESULTS WOULD YOU LIKE?")
which_class = input ("which class?")
if result_type == ("A") or result_type == ("a"):
print("alphabetical order(type:A)")
if result_type == ("B") or result_type == ("b"):
print("results in highest to lowest.")
score_list = deque(maxlen=3)
scores = input("Please enter your score.")
choose = input("do you want to entre another score? y,n")
while choose != "n":
scores = input("Please enter your score.")
choose = input("do you want to entre another score? y,n")
score_list.append(scores)
if choose != "y" :
print(score_list)
print((student_name)+"'s:"+"lowest to largest"+str(heapq.nsmallest(3, score_list)))
print((student_name)+"'s:"+"largest to lowest"+str(heapq.nlargest(3, score_list)))
if result_type == ("C") or result_type == ("c"):
print("results in average order.")
score_list = deque(maxlen=3)
scores = input("Please enter your score.")
choose = input("do you want to entre another score? y,n")
while choose != "n":
scores = input("Please enter the scores.")
choose = input("do you want to entre another score? y,n")
score_list.append(int(scores))
#print(len(score_list))
#print(sum(score_list))
total = (int(sum(score_list)))
length = (int(len(score_list)))
average= (total)/(length)
if choose != "y" :
print(student_name+"'s "+"average score:"+str(average))
#print("average: " +str(average))
这是我如何改进它，我仍然无法弄清楚按字母顺序排序的部分。
答案 0 :(得分：0)
更新，您应该能够粘贴并运行以下代码 但是，你需要自己包装输入循环，这意味着，连接接口/函数调用
import json
class Quize():
def __init__(self):
self.db = {}
def createClass(self, class_name):
self.db[class_name] = {}
def createUser(self, class_name, user_name):
self.db[class_name][user_name] = []
def addScore(self, class_name, user_name, score):
self.db[class_name][user_name].append(score)
self.db[class_name][user_name] = self.db[class_name][user_name][-3:]
def printClass(self, class_name, order = None):
if not order:
print json.dumps(self.db[class_name], indent=4)
else:
to_sort = self.db[class_name]
print 'order', order
if order == 'by highest':
print sorted([ [max(to_sort[name]), name] for name in to_sort ], cmp = lambda x, y : y[0] - x[0])
if order == 'by lowest':
print sorted([ [min(to_sort[name]), name] for name in to_sort ], cmp = lambda x, y : x[0] - y[0])
if order == 'by average':
print sorted([ [sum(to_sort[name]) / len(to_sort[name]), name] for name in to_sort ],
cmp = lambda x, y : y[0] - x[0])
if order == 'by name':
print sorted([ [to_sort[name], name] for name in to_sort ], cmp = lambda x, y : x[1] > y[1])
def printUser(self, class_name, user_name):
print json.dumps(self.db[class_name][user_name], indent=4)
def dump(self):
print json.dumps(self.db, indent = 4)
ins = Quize()
ins.createClass('0302')
ins.createUser('0302', 'jack')
ins.createUser('0302', 'tom')
ins.addScore('0302', 'jack', 99)
ins.addScore('0302', 'jack', 92)
ins.addScore('0302', 'tom', 99)
ins.addScore('0302', 'tom', 92)
ins.addScore('0302', 'tom', 19)
ins.addScore('0302', 'tom', 29)
ins.addScore('0302', 'tom', 66)
ins.printClass('0302', 'by highest')
ins.printClass('0302', 'by lowest')
ins.printClass('0302', 'by average')
ins.printClass('0302', 'by name')
ins.printUser('0302', 'tom')
ins.printUser('0302', 'jack')
ins.printClass('0302')
ins.addScore('0302', 'jack', 11)
ins.addScore('0302', 'jack', 37)
ins.addScore('0302', 'tom', 80)
ins.addScore('0302', 'tom', 72)
ins.printClass('0302', 'by highest')
ins.printClass('0302', 'by lowest')
ins.printClass('0302', 'by average')
ins.printClass('0302', 'by name')
ins.printUser('0302', 'tom')
ins.printUser('0302', 'jack')
ins.printClass('0302')
答案 1 :(得分：0)
这里有很多问题，但我会讨论一些问题。您需要确保将输入转换为int（），否则您将对字符串进行数学运算，这会导致问题。其次，最重要的是，字典不是有序的，所以你永远不会得到相同的最后3个条目。
您可以使用列表推导来获取成绩并对其进行排序，这是其他事情之后的第一件事：因为输入顺序无关紧要。对于接下来的两个，您不能使用字典值，您必须参考您用来跟踪输入成绩的列表。
grade_list = []
class1 = {}
if input('what class would you like? ') == '1':
while True:
student_name = input('name? ')
score = int(input('score? ')) # must convert input to int
grade_list.append(score)
class1[student_name] = score
if input('do you want to enter another student? ') == 'y':
pass
else:
# fetch grades
grades = [v for k, v in class1.items()]
# print highest to lowest
print(sorted(grades, reverse=True))
# print last 3 grades
print(grade_list[-3:])
# print avg of last 3 grades
print(sum(grade_list[-3:]) / 3)
break
输出
what class would you like? 1
name? Abby
score? 11
do you want to enter another student? y
name? Bobby
score? 22
do you want to enter another student? y
name? Charles
score? 33
do you want to enter another student? y
name? Damon
score? 44
do you want to enter another student? n
[44, 33, 22, 11]
[22, 33, 44]
33.0