图像无法使用C＃Desktop Application保存SQLite数据库

Question

我正在尝试将图片框中的图片保存到Sqlite＆amp;使用C＃从SqliteDB检索图片框上的图像。 你在数据库中保存的是什么，你可以在图片中看到数据库数据类型中的图像是blob

当我尝试检索并在图片框中显示图像时，它显示以下错误。

以下是代码：

    using Finisar.SQLite;
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.IO;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;

namespace SQLiteDb
{
    public partial class ImageForm : Form
    {
        public ImageForm()
        {
            InitializeComponent();
        }
        SQLiteConnection sqlite_conn = new SQLiteConnection("Data Source=database.db;Version=3;New=False;Compress=True;");

        private void button2_Click(object sender, EventArgs e)
        {
            //To convert immage into bytes
            Image img = pictureBox1.Image;
            MemoryStream ms = new MemoryStream();
            pictureBox1.Image.Save(ms, System.Drawing.Imaging.ImageFormat.Jpeg);
            byte[] dataByte = ms.ToArray();


           // Saving into database. . 
            sqlite_conn.Open();
            SQLiteCommand cmd_Insert = new SQLiteCommand("Insert into ForImage(ID,FileImage) values ('"+12+"','" + dataByte + "')", sqlite_conn);
            cmd_Insert.ExecuteNonQuery();
        }

        // To Show/load Image in Picturebox 1.
        private void button1_Click(object sender, EventArgs e)
        {
            DialogResult = openFileDialog1.ShowDialog();
            if (DialogResult == DialogResult.OK)
            {
                pictureBox1.Image = new Bitmap(openFileDialog1.FileName);
            }
        }

        private void button3_Click(object sender, EventArgs e)
        {
            sqlite_conn.Open();

            SQLiteCommand cmd = new SQLiteCommand("Select FileImage from ForImage where ID=12", sqlite_conn);
            byte[] imageBytes = (byte[])cmd.ExecuteScalar();
            MemoryStream mm = new MemoryStream(imageBytes);
            Image img = Image.FromStream(mm);
            pictureBox2.Image = img;

        }
    }
}

请告诉我代码中的问题。

Answer 1

以下是上述问题的解决方案和工作代码：

using Finisar.SQLite;
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.IO;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;

namespace SQLiteDb
{
    public partial class Final_Form : Form
    {
        public Final_Form()
        {
            InitializeComponent();
        }
        SQLiteConnection con = new SQLiteConnection("Data Source=database.db;Version=3;New=False;Compress=True;");
        Image image;
        private void Upload_image_Click(object sender, EventArgs e)
        {
            DialogResult = openFileDialog1.ShowDialog();
            if (DialogResult == DialogResult.OK)
            {
                pictureBox1.Image = new Bitmap(openFileDialog1.FileName);
                image = pictureBox1.Image;
            }
        }

        private void Save_Click(object sender, EventArgs e)
        {
            byte[] imagesBytes = Image2Byte(pictureBox1.Image);
            SaveImage(imagesBytes);
        }

        private void Show_Click(object sender, EventArgs e)
        {
            LoadImageFromDb();
        }
        //Retrive Image Code. . 

        private void LoadImageFromDb()
        {
            con.Open();
            SQLiteCommand cmd = new SQLiteCommand("Select FileImage from ForImage where ID='86';", con);
            byte[] arrayFromDb = (byte[])cmd.ExecuteScalar();
            con.Close();
            pictureBox2.Image = ByteToImage(arrayFromDb);
        }
        private Image ByteToImage(byte[] toConvert)
        {
            MemoryStream toImage = new MemoryStream(toConvert);
            Image imageFromBytes = Image.FromStream(toImage);
            return imageFromBytes;
        }
        //Picture Save Methods Define Here. . 
        #region
        private void SaveImage(byte[] imageBytes2Save)
        {
            string Query_ = "INSERT INTO ForImage (ID,FileImage) VALUES (86,@0);";
            SQLiteParameter PicParam = new SQLiteParameter("@0", DbType.Binary);
            PicParam.Value = imageBytes2Save;

            con.Open();
            SQLiteCommand cmd = new SQLiteCommand(Query_,con);
            cmd.Parameters.Add(PicParam);
            cmd.ExecuteNonQuery();
            con.Close();
        }

        private byte[] Image2Byte(Image imageToconvert)
        {
            MemoryStream memoryStream = new MemoryStream();
            imageToconvert.Save(memoryStream, System.Drawing.Imaging.ImageFormat.Jpeg);
            byte[] bytesOfImage = memoryStream.ToArray();
            return bytesOfImage;
        }

        #endregion




    }
}

//这是输出

• 将图片上传到图片框

• 将图片保存到数据库（SQLITE）

• 从数据库中检索以在Picturebox中显示

我是如何解决问题的？
Ans：通过在查询中放置参数来保存数据库中的图像。