我必须向我的iPhone应用程序中的Web服务发送https GET请求,该应用程序是在Swift 1.2中开发的。
我正在尝试构造查询字符串参数,但在发送到服务器之前必须对它们进行编码。
密码包含'&'字符内。期待编码'&'字符到'%26'但不工作......
刚刚进行了一次测试'%'。按预期工作'%'提供'%25'。但不能转换'&'签....
尝试以下方式:
var testPassword1: String = "mypassword&1"
var testPassword2: String = "mypassword%1"
// Try to encode 'testPassword1'
testPassword1.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)!
testPassword1.stringByAddingPercentEncodingWithAllowedCharacters(.URLHostAllowedCharacterSet())!
// Try to encode 'testPassword2'
testPassword2.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)!
testPassword2.stringByAddingPercentEncodingWithAllowedCharacters(.URLHostAllowedCharacterSet())!
我已完成上述测试,以下是回复
想知道这样做的正确方法。感谢。
答案 0 :(得分:3)
您应该使用NSURLComponents
完成任务。
给定一个URL字符串,创建一个url-components:
let urlString = "http://example.com"
let urlComponents = NSURLComponents(string: urlString)!
给定一个查询参数容器(可能是一个字典,或一个(String,String?)元组的数组),创建一个NSURLQueryItems数组:
let queryParameters: [String: String?] = ["param": "az09-._~!$&'()*+,;=:@/?", "reserved": ":/?#[]@!$&'()*+,;="]
var queryItems = queryParameters.map { NSURLQueryItem(name: $0.0, value: $0.1) }
将查询组件附加到url-components:
urlComponents.queryItems = queryItems.count > 0 ? queryItems : nil
print(urlComponents.string!)
打印:
http://example.com?reserved=:/?%23%5B%5D@!$%26'()*+,;%3D¶m=az09-._~!$%26'()*+,;%3D:@/?
答案 1 :(得分:0)
我使用这样的实用工具方法在GET请求中对值进行URL编码:
@interface NSString (Ext)
@property (nonatomic, readonly) NSString *urlEncoded;
@end
@implementation NSString (Ext)
- (NSString *)urlEncoded {
NSMutableCharacterSet *const allowedCharacterSet = [NSCharacterSet URLQueryAllowedCharacterSet].mutableCopy;
// See https://en.wikipedia.org/wiki/Percent-encoding
[allowedCharacterSet removeCharactersInString:@"!*'();:@&=+$,/?#[]"]; // RFC 3986 section 2.2 Reserved Characters (January 2005)
NSString *const urlEncoded = [self stringByAddingPercentEncodingWithAllowedCharacters:allowedCharacterSet];
return urlEncoded;
}
@end
答案 2 :(得分:0)
如果您需要编码&字符,您可以使用以下内容:
var testPassword1: String = "mypassword&1"
testPassword1.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)!
testPassword1.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet(charactersInString: "&").invertedSet)!