Question

我想在java中执行javascript代码。所以我写了如下所示的代码。但在执行期间，它在中线失败。说错误是'缺失;在陈述之前'。

JavascriptExecutor js = (JavascriptExecutor)driver;

String g=(String) js.executeScript("var r = confirm('r u ready');"+"if(r==true) { Var b='ok'; } return b;");

System.out.println(g);

Answer 1

您在变量声明中遇到问题，请将Var替换为var：

String g=(String) js.executeScript("var r = confirm('r u ready'); var b; if(r == true) { b='ok'; } return b;");

Answer 2

"(function() {var r,b; r = confirm('r u ready'); if(r == true) { b='ok'; } return b;})()"

Answer 3

如果您的目标是在关闭dilog之前阻止执行，那么您应该使用executeAsyncScript而不是executeScript。

以下是显示确认对话框并等待某人关闭它的示例：

WebDriver driver= new ChromeDriver();
driver.manage().timeouts().setScriptTimeout(20, TimeUnit.SECONDS);

driver.get("http://stackoverflow.com");

Boolean confirm = (Boolean)((JavascriptExecutor)driver).executeAsyncScript(
  "var callback = arguments[0]; setTimeout(function(){ " +
  "  callback(window.confirm('Are you ready?'));       " +
  "}, 1);");

另一个显示提示对话框并等待某人键入一些文本并将其关闭：

WebDriver driver= new ChromeDriver();
driver.manage().timeouts().setScriptTimeout(20, TimeUnit.SECONDS);

driver.get("http://stackoverflow.com");

// display a confirm dialog and waits for someone to type some text
String prompt = (String)((JavascriptExecutor)driver).executeAsyncScript(
  "var callback = arguments[0]; setTimeout(function(){ " +
  "  callback(window.prompt('Give me some text!'));    " +
  "}, 1);");

// display the text typed by the user
System.out.println(prompt);

在java中执行javascript代码时出错

3 个答案: