Question

尝试使用RestSharp创建一个通用方法来调用REST端点，我遇到的唯一问题是将内容作为动态返回。

Response.Data为null，Response.Content始终为字符串。我希望返回值至少是一个匿名类型。

public T Call<T>(string url, Method method = Method.GET, ResponseType type = ResponseType.JSON, params Parameter[] parameters)
{
    var request = new RestRequest(url, method);

    switch (type)
    {
        case ResponseType.JSON:
            request.AddHeader("Content-Type", "application/json");
            request.AddHeader("Accept", "application/json");
            request.RequestFormat = DataFormat.Json;
            break;
        case ResponseType.XML:
            request.AddHeader("Content-Type", "application/xml");
            request.AddHeader("Accept", "application/xml");
            request.RequestFormat = DataFormat.Xml;
            break;
    }

    foreach (var parameter in parameters)
        request.AddParameter(parameter);

    var response = _client.Execute<dynamic>(request);

    if (!string.IsNullOrEmpty(response.ErrorMessage) || response.ErrorException != null)
        throw new System.Exception(response.ErrorMessage, response.ErrorException);

    return response.Data;
}

Answer 1

鉴于你有类型T，你不能这样做：

var response = _client.Execute<T>(request);

动态返回序列化的RestSharp结果

1 个答案: