Gulp任务评论

Question

我是否有任何gulp任务来评论代码行？我知道很多删除行的任务，但我想注释掉例如

line1  var a = 'mr';
line2  var b = 'mrs;
line3  var c = 'apple';
line4  var d = 'plum';
line5  var e = 'pear';
line6  var f = 'hat';
line7  var g = 'table';
line8  var h = 'spoon';
line9  var i = 'car';
line10  var j = 'ladder';

有了上述内容，我想注释掉例如line2和line6，结果将是：

line1  var a = 'mr';
//line2  var b = 'mrs;
line3  var c = 'apple';
line4  var d = 'plum';
line5  var e = 'pear';
//line6  var f = 'hat';
line7  var g = 'table';
line8  var h = 'spoon';
line9  var i = 'car';
line10  var j = 'ladder';

Answer 1

在NPM上...

https://www.npmjs.com/package/gulp-uncomment 看起来“ gulp-uncomment”将有助于删除生产中不必要的注释...

https://www.npmjs.com/package/gulp-strip-code 而“ gulp-strip-code”将允许您删除不需要的代码块。本质上是“评论”它们...