Question

我正在尝试使用python和美丽的汤来提取下面标签的内容部分：

<meta property="og:title" content="Super Fun Event 1" />
<meta property="og:url" content="http://superfunevents.com/events/super-fun-event-1/" />

我正在使用BeautifulSoup来加载页面并找到其他内容（这也会从隐藏在源代码中的id标记中获取文章ID），但我不知道正确的搜索方式html并找到这些位，我尝试过find和findAll的变种无济于事。代码迭代目前的URL列表......

#!/usr/bin/env python
# -*- coding: utf-8 -*-

#importing the libraries
from urllib import urlopen
from bs4 import BeautifulSoup

def get_data(page_no):
    webpage = urlopen('http://superfunevents.com/?p=' + str(i)).read()
    soup = BeautifulSoup(webpage, "lxml")
    for tag in soup.find_all("article") :
        id = tag.get('id')
        print id
# the hard part that doesn't work - I know this example is well off the mark!        
    title = soup.find("og:title", "content")
    print (title.get_text())
    url = soup.find("og:url", "content")
    print (url.get_text())
# end of problem

for i in range (1,100):
    get_data(i)

如果有人可以帮我排序，找到og：title和og：内容太棒了！

Answer 1

将meta标记名称作为find()的第一个参数。然后，使用关键字参数检查特定属性：

title = soup.find("meta",  property="og:title")
url = soup.find("meta",  property="og:url")

print(title["content"] if title else "No meta title given")
print(url["content"] if url else "No meta url given")

如果您知道标题和网址元素属性始终存在，则此处的if / else检查将是可选的。

Answer 2

试试这个：

soup = BeautifulSoup(webpage)
for tag in soup.find_all("meta"):
    if tag.get("property", None) == "og:title":
        print tag.get("content", None)
    elif tag.get("property", None) == "og:url":
        print tag.get("content", None)

Answer 3

我要解决的方法如下：
（与属性列表一起使用时更整洁...）

title = soup.find("meta",  {"property":"og:title"})
url = soup.find("meta",  {"property":"og:url"})

# Using same method as above answer
title = title["content"] if title else None
url = url["content"] if url else None

Answer 4

来自 Jinesh Narayanan 的代码：https://gist.github.com/jineshpaloor/6478011 对本次讨论有效。

from bs4 import BeautifulSoup
import requests
def main():
    r = requests.get('http://www.sourcebits.com/')
    soup = BeautifulSoup(r.content, features="lxml")

    title = soup.title.string
    print ('TITLE IS :', title)

    meta = soup.find_all('meta')

    for tag in meta:
        if 'name' in tag.attrs.keys() and tag.attrs['name'].strip().lower() in ['description', 'keywords']:
            # print ('NAME    :',tag.attrs['name'].lower())
            print ('CONTENT :',tag.attrs['content'])

if __name__ == '__main__':
    main()

Answer 5

您可以使用gazpacho来获取meta标记内的内容：

from gazpacho import Soup

html = """\
<meta property="og:title" content="Super Fun Event 1" />
<meta property="og:url" content="http://superfunevents.com/events/super-fun-event-1/" />
"""

soup = Soup(html)
soup.find("meta", {"property": "og:title"}).attrs['content']

哪个会输出：

'Super Fun Event 1'

使用BeautifulSoup和Python获取元标记内容属性

5 个答案: