Question

我试图让最常见的小时成为一个数组。 foreach循环是分割值并仅使用小时

获取数组

 foreach ($times as $k => $v) {
    $avtime[$k] = explode("T", $v);
    $avtimeb[$k] = $avtime[$k][1];
    foreach ($avtimeb as $kb => $vb) {
        $avtimec[$kb] = explode(":", $vb);
        $avtimed[$kb] = $avtimec[$kb][0];
    }
}

和print_r($avtimed);生成以下内容：

Array
(
    [0] => 08
    [1] => 08
    [2] => 08
    [3] => 08
    [4] => 09
    [5] => 09
    [6] => 08
    [7] => 08
    [8] => 08
    [9] => 10
    [10] => 09
    [11] => 09
    [12] => 10
    [13] => 11
    [14] => 07
    [15] => 08
    [16] => 13
    [17] => 07
    [18] => 08
    [19] => 08
    [20] => 08
    [21] => 09
    [22] => 09
    [23] => 09
    [24] => 09
)

现在我需要从上面得到最常见的价值。

Answer 1

使用外部阵列可以存储类似的小时。然后浏览数组以获得公共小时。

<强>技术

openFolder_1
openFolder_2

Answer 2

最后一个是：

foreach ($times as $k => $v) {
    $avtime[$k] = explode("T", $v);
    $avtimeb[$k] = $avtime[$k][1];
    foreach ($avtimeb as $kb => $vb) {
        $avtimec[$kb] = explode(":", $vb);
        $avtimed[$kb] = $avtimec[$kb][0];
    }
}
$count = array_count_values($avtimed);
arsort($count); 
$keys = array_keys($count);
echo "The most occuring value is $keys[0] and the second one is $keys[1]";

谢谢大家的帮助。

计算php数组

2 个答案: