Question

我正在尝试了解嵌套的golang地图我有一个如下地图我如何迭代所有键？

Data:
  - name: "foo"
    bar1: 0
      k1: val1
      k2:
         val2
         val3
    bar2: 1
      k3: val4
      k4: val5
      k3: val4
      k4: val5

Answer 1

您必须将数据解组为映射（map [interface {}] interface {}或map [string] interface {}），然后您必须检查键的值的类型。您可以使用yaml.v2包，可能有更清晰的接口，有助于检测值的类型。否则，请检查迭代键并打印值的示例：

package main

import (
    "fmt"
    "gopkg.in/yaml.v2"
    "reflect"
    "strings"
)

var data = `
Data:
    - name: "foo"
      bar1: 0
      k1: val1
      k2:
         val2
         val3
      bar2: 1
      k3: val4
      k4: val5
      k5: val5
      k6: val6
`

func printVal(v interface{}, depth int) {
    typ := reflect.TypeOf(v).Kind()
    if typ == reflect.Int || typ == reflect.String {
        fmt.Printf("%s%v\n", strings.Repeat(" ", depth), v)
    } else if typ == reflect.Slice {
        fmt.Printf("\n")
        printSlice(v.([]interface{}), depth+1)
    } else if typ == reflect.Map {
        fmt.Printf("\n")
        printMap(v.(map[interface{}]interface{}), depth+1)
    }

}

func printMap(m map[interface{}]interface{}, depth int) {
    for k, v := range m {
        fmt.Printf("%sKey:%s", strings.Repeat(" ", depth), k.(string))
        printVal(v, depth+1)
    }
}

func printSlice(slc []interface{}, depth int) {
    for _, v := range slc {
        printVal(v, depth+1)
    }
}

func main() {
    m := make(map[string]interface{})

    err := yaml.Unmarshal([]byte(data), &m)
    if err != nil {
        panic(err)
    }
    for k, v := range m {
        fmt.Printf("Key:%s ", k)
        printVal(v, 1)
    }
}

如何迭代golang

1 个答案: