Question

我有三个表如下：

invent_accessory ID，代码，细节，is_length

invent_price_accessory ID，invent_accessory_id_fk，价格，颜色

invent_price_accessory_length ID，invent_accessory_id_fk，价格，颜色

如何组合这三个表，以便我可以获得 id，code，detal，is_length，price，color

我已完成以下操作，但它不会返回任何数据：

 public function getAccessoryInventPrice(){

  $accessory=DB::table('invent_accessory')
        ->select('invent_accessory.id as accessory_id')
        ->join('invent_price_accessory','invent_price_accessory.invent_accessory_id_fk','=','invent_accessory.id')
        ->join('invent_price_accessory_length','invent_price_accessory_length.invent_accessory_id_fk','=','invent_accessory.id')
      ->get();

  return $accessory;

 }

我猜我必须首先在 invent_price_accessory 和 invent_price_accessory_length 之间进行联合，然后加入 invent_accessory ？我该怎么做呢？请帮助。

Answer 1

我的猜测是对的!!我能够通过以下方式解决这个问题：

  public function getAccessoryInventPrice(){


    $data1=\DB::table('invent_price_accessory')->select('accessory_code_id','color_id','rate');
    $data2=\DB::table('invent_price_acc_length')->select('accessory_code_id','color_id','rate')
              ->union($data1);

    $query= \DB::table(\DB::raw("({$data2->toSql()}) as invent_price"))

            ->join('invent_accessory','invent_price.accessory_code_id','=','invent_accessory.id')
            ->join('invent_color','invent_price.color_id','=','invent_color.id')
            ->select('invent_accessory.id','code','sl_detail','is_length','rate','invent_color.name')
            ->orderBy('invent_accessory.id','asc')
            ->get();
              return $query;

 }

laravel加入三张桌子

1 个答案: