matplotlib数据点绘制但它们之间没有线？

Question

我想在同一轴上绘制包含多个数据集的折线图，因此标记显示但不显示。我真的无法看到我做错了什么。有人可以再戴上另一双眼睛吗？

这是数据打印：

looking at 2015-08-05 83.0 AA attribs sector= Materials shape= o kolor= b x = 2015-08-05 y =  83.0
looking at 2015-08-06 50.0 AA attribs sector= Materials shape= o kolor= b x = 2015-08-06 y =  50.0
looking at 2015-08-07 42.0 AA attribs sector= Materials shape= o kolor= b x = 2015-08-07 y =  42.0
looking at 2015-08-10 75.0 AA attribs sector= Materials shape= o kolor= b x = 2015-08-10 y =  75.0

以下是代码段：

for count, symb in enumerate(my_symbols):
   sector = sector_format[str(sym_sect[symb])][0]
   shape = sector_format[str(sym_sect[symb])][1]
   kolor = sector_format[str(sym_sect[symb])][2]
   x = my_dates[count]
   y = rank_2010[count]
   print("looking at",x,y,symb,"attribs",
         "sector=",sector,
         "shape=",shape,
         "kolor=",kolor,
         "x =",x,
         "y = ",y)

  if symb == 'AA' or symb == "AAPL":
     plt.plot(x,y,lw=5,color=kolor,linestyle='solid',marker=shape)

plt.title('hv 20 to 10 ranks')
plt.xlabel('dates')
plt.ylabel('symbol ranks')
plt.show()

Answer 1

您的问题是您多次致电plot，希望它将您提供的数据收集到一组中。这不是plot的工作方式。您需要形成一个数据集（图中的一个“线”）并将其传递给plot。有点像：

x_list = []
y_list = []

for count, symb in enumerate(my_symbols):
   sector = sector_format[str(sym_sect[symb])][0]
   shape = sector_format[str(sym_sect[symb])][1]
   kolor = sector_format[str(sym_sect[symb])][2]
   x = my_dates[count]
   y = rank_2010[count]
   print("looking at",x,y,symb,"attribs",
         "sector=",sector,
         "shape=",shape,
         "kolor=",kolor,
         "x =",x,
         "y = ",y)

  if symb == 'AA' or symb == "AAPL":
      x_list.append(x)
      y_list.append(y)

plt.plot(x_list,y_list,lw=5,color=kolor,linestyle='solid',marker=shape)

plt.title('hv 20 to 10 ranks')
plt.xlabel('dates')
plt.ylabel('symbol ranks')
plt.show()

这可能不是您想要的。我不清楚你要用不同的颜色和标记做什么，所以你可能需要修改它。但是，我认为至少应该让你朝着正确的方向前进。