Question

我正在考虑这样的列表列表。

    var myList = new List<List<string>>();
    myList.Add(new List<string> { "#16", "100%", "Monitor" });
    myList.Add(new List<string> { "#19", "98%", "Guide" });
    myList.Add(new List<string> { "#77", "0%", "Cord" });

来自这样的代码。

    string mySource = @"
    #16
    100%
    Monitor
    #19
    98%
    Guide
    #77
    0%
    Cord
    ";
    var myPattern = @"#(\d+)\r\n(\d+)%\r\n([^\r\n]*)\r\n";
    var myCollection = Regex.Matches(mySource, myPattern, RegexOptions.Singleline)
    .Cast<Match>()
    .Select(x => Regex.Split(x.Value, "\r\n"))
    .ToList();

显然位于＆＃34;匹配＆＃34;它有一个数组。

如何将其更改为列表列表？

此致

Answer 1

只需使用ToList扩展程序Array转换为List

string mySource = @"
#16
100%
Monitor
#19
98%
Guide
#77
0%
Cord
";
var myPattern = @"#(\d+)\r\n(\d+)%\r\n([^\r\n]*)\r\n";
var myCollection = Regex.Matches(mySource, myPattern, RegexOptions.Singleline)
.Cast<Match>()
.Select(x => Regex.Split(x.Value, "\r\n").ToList())
.ToList();

Answer 2

显然，在“匹配”的中间，它有一个数组。

显然你必须把它转换成一个列表。

//.Select(x => Regex.Split(x.Value, "\r\n"))
.Select(x => Regex.Split(x.Value, "\r\n").ToList())

var pattern = string.Join(@"\r\n", @"(?<id>#\d+)", @"(?<percent>\d+%)", @"(?<name>\w+)");
Regex.Matches(mySource, pattern, RegexOptions.Singleline)
    .Cast<Match>()
    .Select(m => new[] //or you can use : m => new List<string>
    {
        m.Groups["id"].Value,
        m.Groups["percent"].Value,
        m.Groups["name"].Value
    })
    .ToList();

LINQ to Object基本代码

2 个答案: