Question

我有以下JSON-String数组

[  
    {  
        "firstName": "Patrick",
        "lastName": "Smith",
        "loginName":"test0003@test.com",
        "Country":"US",
        "phoneNumber": "287 125-1434",
        "status": "340"
    },
    {  
        "firstName": "Bob",
        "lastName": "Williams",
        "loginName":"test0002@test.com",
        "Country":"US",
        "phoneNumber": "213 111-9943",
        "status": "215"
    },
    {  
        "firstName": "John",
        "lastName": "Johnson",
        "loginName":"test0001@test.com",
        "Country":"DE",
        "phoneNumber": "212 555-1234",
        "status": "340"
    },
    {  
        "firstName": "John",
        "lastName": "Johnson",
        "loginName":"test0001@test.com",
        "Country":"DE",
        "phoneNumber": "212 555-1234",
        "status": "215"
    },
    {  
        "firstName": "John",
        "lastName": "Johnson",
        "loginName":"test0001@test.com",
        "Country":"DE",
        "phoneNumber": "212 555-1234",
        "status": "167"
    },
    {  
        "firstName": "George",
        "lastName": "Jones",
        "loginName":"test0004@test.com",
        "Country":"FR",
        "phoneNumber": "217 987-2634",
        "status": "340"
    }
]

我只需返回此部分

    {  
        "firstName": "John",
        "lastName": "Johnson",
        "loginName":"test0001@test.com",
        "Country":"DE",
        "phoneNumber": "212 555-1234",
        "status": "167"
    }

为 loginName 和 status

提供值

我需要创建一个如下所示的方法。

public String filterJsonArray(String array, String keyOne, Object valueOne, String keyTwo, Object valueTwo)  throws ParseException {

}

有人可以告诉我如何实现这个目标。

Answer 1

使用杰克逊，这是我能想到的最粗略的片段：

#include <stdio.h>

int main (int argc, char **argv) {
    for (;;) {
        char buf;
        fread(&buf, 1, 1, stdin);
        if ('q' == buf)
            break;
        fwrite(&buf, 1, 1, stdout);
        fflush(stdout);
    }

    return 0;
}

当然它只会返回给定对的第一场比赛。如果您需要所有值，请改为返回列表并在循环内填充它。

Answer 2

我使用JSONObject，这是另一种解析方法。 1.使用JSONArray解析 2.循环数组并读入UserProfile对象 3.将其存储在HashMap中以使用密钥

import java.util.HashMap;
import java.util.Map;
import org.json.*;

class UserProfile{
  String loginName;
  int status;
  String firstName;
  String key;

  UserProfile(){

  }

  String getLoginName(){
    return loginName;
  }

  String getFirstName(){
    return firstName;
  }

  void setKey(String key){
    this.key = key;
  }

  void setLoginName(String loginName){
    this.loginName = loginName;
  }

  void setStatus(int status){
    this.status = status;
  }

  void setFirstName(String firstName){
    this.firstName = firstName;
  }
}

public class JSONObjParser {

  public static void main(String[] args){
    Map<String, UserProfile> map = new HashMap<String, UserProfile>();

    String msg ="[{ firstName: Patrick, lastName: Smith, loginName:test0003@test.com, Country:US, phoneNumber: 287 125-1434, status: 340 }, {  firstName: Bob, lastName: Williams, loginName:test0002@test.com, Country:US, phoneNumber: 213 111-9943, status: 215 }]";
    JSONArray jsonarray = new JSONArray(msg);
    for (int i = 0; i < jsonarray.length(); i++) {
        JSONObject jsonobject = jsonarray.getJSONObject(i);
        String loginName = jsonobject.getString("loginName");
        int status = jsonobject.getInt("status");
        String firstName = jsonobject.getString("firstName");

        UserProfile profile = new UserProfile();
        profile.setFirstName(firstName);
        profile.setLoginName(loginName);
        profile.setStatus(status);
        String key = loginName + Integer.toString(status);
        map.put(key, profile);
    }

    for (String key : map.keySet()) {
        UserProfile profile = map.get(key);
        System.out.println("Key = " + key + ", FirstName = " + profile.getFirstName());
    }

  }
}

如何根据属性过滤JSON String数组？

2 个答案: