我正在使用GoogleApiClient来获取用户位置。我创建了一个单例类来获取用户位置。这是班级:
public class LocationUtils {
private static LocationUtils locationUtils;
private GoogleApiClient googleApiClient;
public static LocationUtils getInstance() {
if(locationUtils == null)
locationUtils = new LocationUtils();
return locationUtils;
}
private LocationUtils() {}
public Location getLocation(Context context){
final Location[] location = {null};
googleApiClient = new GoogleApiClient.Builder(App.getContext())
.addConnectionCallbacks(new GoogleApiClient.ConnectionCallbacks() {
@Override
public void onConnected(Bundle bundle) {
if(ContextCompat.checkSelfPermission(App.getContext(), Manifest.permission.ACCESS_FINE_LOCATION) == PackageManager.PERMISSION_GRANTED)
location[0] = LocationServices.FusedLocationApi.getLastLocation(googleApiClient );
googleApiClient.disconnect();
}
@Override
public void onConnectionSuspended(int i) {
}
})
.addOnConnectionFailedListener(new GoogleApiClient.OnConnectionFailedListener() {
@Override
public void onConnectionFailed(ConnectionResult connectionResult) {
}
})
.addApi( LocationServices.API )
.build();
googleApiClient.connect();
return location[0];
}
}
我想通过LocationUtils.getInstance()。getLocation(context)获取用户位置。当我调用getLocation()方法时,它应该连接到GoogleApiClient,返回用户位置并断开连接到每次调用的GoogleApiClient。但是当我调用该方法时,它返回null。主线程不等待onConnected()方法并将location对象返回为null。它如何等待onConnect()方法?或者如何在onConnected()中返回Location对象?
根据Tim Castelijns的回答已解决
首先我创建了一个界面:
public interface LocationCallbackInterface {
void onComplete(Location location);
}
然后在getLocationMethod()中使用它:
public void getLocation(Context context,final LocationCallbackInterface callback){
final Location[] location = {null};
googleApiClient = new GoogleApiClient.Builder(App.getContext())
.addConnectionCallbacks(new GoogleApiClient.ConnectionCallbacks() {
@Override
public void onConnected(Bundle bundle) {
if(ContextCompat.checkSelfPermission(App.getContext(), Manifest.permission.ACCESS_FINE_LOCATION) == PackageManager.PERMISSION_GRANTED) {
location[0] = LocationServices.FusedLocationApi.getLastLocation(googleApiClient);
//Toast.makeText(App.getContext(), "location came :" + location[0].toString(), Toast.LENGTH_LONG).show();
callback.onComplete(location[0]);
}
googleApiClient.disconnect();
}
@Override
public void onConnectionSuspended(int i) {
}
})
.addOnConnectionFailedListener(new GoogleApiClient.OnConnectionFailedListener() {
@Override
public void onConnectionFailed(ConnectionResult connectionResult) {
}
})
.addApi( LocationServices.API )
.build();
googleApiClient.connect();
}
然后在一个活动中调用该方法:
LocationUtils.getInstance().getLocation(getActivity(), new LocationCallbackInterface() {
@Override
public void onComplete(Location location) {
if (location != null) {
Toast.makeText(getActivity(), "location :" + location.toString(), Toast.LENGTH_SHORT).show();
initCamera(location);
} else
Toast.makeText(getActivity(), "location is null", Toast.LENGTH_SHORT).show();
}
});
答案 0 :(得分:2)
由于该位置是异步获取的,因此您应该使用回调来返回该位置,否则您的返回值将始终为null,因为googleApiClient尚未完成。
定义像这样的界面
public interface LocationCallback {
void onComplete(Location location);
}
更改
public Location getLocation(Context context)
到
public Location getLocation(Context context, LocationCallback callback)
并像这样称呼它
LocationUtils.getLocation(context, new LocationCallback() {
@Override
onComplete(Location location) {
// when this is called, you will have a location.
}
});