Question

正如标题所说。有没有办法在不更改架构密码的情况下使用＆符密码创建数据库链接？

CREATE DATABASE LINK DBLINK_NAME
CONNECT TO SCHEMA_NAME IDENTIFIED BY p&ssword 
USING '(DESCRIPTION=(ADDRESS=(PROTOCOL=TCP)(Host=host.name.com)(Port=1521))(CONNECT_DATA=(SID=host)))';

Answer 1

密码中的“＆”是棘手的，因为它是定义字符，您可以通过以下方式查看：

show define;

您应该能够通过将密码括在引号中来规避这一点，然后当您被要求“输入替换变量”时，输入＆符号和尾随字符，如下所示：

SQL> CREATE DATABASE LINK DBLINK_NAME
CONNECT TO SCHEMA_NAME IDENTIFIED BY "p&ssword" 
USING '(DESCRIPTION=(ADDRESS=(PROTOCOL=TCP)(Host=host.name.com)(Port=1521))(CONNECT_DATA=(SID=host)))';

Enter value for ssword: &ssword

old    1:      CREATE DATABASE LINK DBLINK_NAME
    CONNECT TO SCHEMA_NAME IDENTIFIED BY "p&ssword" 
    USING '(DESCRIPTION=(ADDRESS=(PROTOCOL=TCP)(Host=host.name.com)(Port=1521))(CONNECT_DATA=(SID=host)))';
new    1:     CREATE DATABASE LINK DBLINK_NAME
    CONNECT TO SCHEMA_NAME IDENTIFIED BY "p&ssword" 
    USING '(DESCRIPTION=(ADDRESS=(PROTOCOL=TCP)(Host=host.name.com)(Port=1521))(CONNECT_DATA=(SID=host)))';

Database link created.

Answer 2

通过使用set escape on和转义＆符号来解决它

SET ESCAPE ON;
CREATE DATABASE LINK DBLINK_NAME
CONNECT TO SCHEMA_NAME IDENTIFIED BY p\&ssword 
USING '(DESCRIPTION=(ADDRESS=(PROTOCOL=TCP)(Host=host.name.com)(Port=1521))(CONNECT_DATA=(SID=host)))';

如何在密码中创建一个带符号（＆amp;）的数据库链接

2 个答案: