Question

我有一个像

这样的外部表格

CREATE EXTERNAL TABLE TAB(ID INT, NAME STRING) PARTITIONED BY(YEAR INT, MONTH STRING , DATES INT) ROW FORMAT DELIMITED FIELDS TERMINATED BY '\t';

我有像

这样的数据

/user/input/2015/jan/1;
/user/input/2015/jan/30

像2000年到2016年那样，每年有12个月零30天;

ALTER TABLE TAB ADD PARTITION(year = '2015', month = 'jan',dates = '5') LOCATION '/user/input/2015/jan/1';

如果我这样做，我只得到一天的数据;

select * from TAB where (year = '2015', month = 'jan',dates = '5');

如果我跑

select * from TAB where (year = '2015', month = 'jan',dates = '6');

我没有收到任何数据。请帮我解释如何改变上述场景的表格

Answer 1

create table tab(id int,name string,dt string) partitioned by (year string,month string);

create table samp(id int,name string,dt string) row format delimited fields terminated by '\t';

load data inpath '\dir' into table samp;
insert overwrite table tab partition (y,m) select id,name dt,YEAR(dt),MONTH(dt) from samp;

Answer 2

ALTER TABLE TAB ADD PARTITION(year = '2015', month = 'jan',dates = '5') LOCATION '/user/input/2015/jan/1';您需要1天，因为您在位置值中指定了1个文件

在5天内创建分区，如下所示

ALTER TABLE TAB 
ADD PARTITION(dates <= '5') 
LOCATION '/user/input/2015/jan/';

Answer 3

alter table with all dates only选项，我跟着一样喜欢＆＃34; ALTER TABLE TAB添加分区（年=＆＃39; 2015＆＃39;，月=＆＃39; jan＆＃39;，date =＆＃39; 5＆＃39;）LOCATION＆＃39; / user /输入/ 2015 / JAN / 1＆＃39 ;; ＆＃34;

按日期划分Hive分区？

3 个答案: