Question

我注意到在序列化一个简单的对象时我丢失了数组内容，并且我认为我会以某种方式重写数组。如何正确地构造代码，允许从最初启动的对象中保存数据？

<?php

class MyClass {

    private $array;

    function __construct($array) {
        $this->array = $array;
    }

    public function __sleep() {
        return $this->array;
    }
}

$array = array(
    'i1' => 1,
    'i2' => 2,
    'i3' => 3,
    'i4' => 4
);

$obj = new MyClass($array);
$ser = serialize($obj);
$des = unserialize($ser);

print_r($obj);
echo '<br><br>';
print_r($ser);
echo '<br><br>';
print_r($des);
?>

输出：

MyClass Object ( [array:MyClass:private] => Array ( [i1] => 1 [i2] => 2 [i3] => 3 [i4] => 4 ) )

O:7:"MyClass":4:{s:1:"1";N;s:1:"2";R:2;s:1:"3";R:2;s:1:"4";R:2;}

MyClass Object ( [array:MyClass:private] => [1] => [2] => [3] => [4] => )

Answer 1

尝试实施Serializable的{{1}}接口。

MyClass

Answer 2

在std::map::find我们可以找到解释如何使用

该函数在任何序列化之前运行。它可以清理该对象应该返回一个名称的数组应该序列化的那个对象的变量。

我必须返回它的名字，而不是只返回__sleep中的私有变量。

<?php

class MyClass {

    private $array;
    private $test;

    function __construct($array, $test) {
        $this->array = $array;
        $this->test = $test;
    }

    public function __sleep() {        
        return array('array', 'test');
    }
}

$test = 'test';
$array = array(
    'i1' => 1,
    'i2' => 2,
    'i3' => 3,
    'i4' => 4
);

$obj = new MyClass($array, $test);
$ser = serialize($obj);
$des = unserialize($ser);

print_r($obj);
echo '<br><br>';
print_r($ser);
echo '<br><br>';
print_r($des);

结果：

MyClass Object ( [array:MyClass:private] => Array ( [i1] => 1 [i2] => 2 [i3] => 3 [i4] => 4 ) [test:MyClass:private] => test )

O:7:"MyClass":2:{s:14:"MyClassarray";a:4:{s:2:"i1";i:1;s:2:"i2";i:2;s:2:"i3";i:3;s:2:"i4";i:4;}s:13:"MyClasstest";s:4:"test";}

MyClass Object ( [array:MyClass:private] => Array ( [i1] => 1 [i2] => 2 [i3] => 3 [i4] => 4 ) [test:MyClass:private] => test )

序列化和反序列化时阻止对象重写

2 个答案: