这是我的代码
#include<iostream>
#include<map>
#include<vector>
#include<algorithm>
#include<string>
#include<math.h>
#include<bitset>
#include<cstring>
#include<sstream>
#include<iomanip>
#include<queue>
using namespace std;
int d1[] = { 0,0,1,-1,1,-1 ,1,-1 };
int d2[] = { -1,1,0,0,1 ,-1,-1,1 };
string vec[200 + 5];
int counter = 0;
long long int floodfill(int n1, int n2, char c1, char c2,int ss)
{
if (n1 < 0 || n1 >= ss || n2 < 0||n2>=vec[n1].length())
return 0;
if (vec[n1][n2] != c1) return 0;
long long int ans = 1;
vec[n1][n2] = c2;
for (int i = 0; i < 8; i++)
ans = ans + floodfill(n1 + d2[i], n2 + d1[i], c1, c2,ss);
return ans;
}
int floodfill2(int n1, int n2, char c1, char c2,int ss)
{
if (n1 < 0 || n1 >= ss || n2 < 0 || n2 >= vec[n1].length())
return 0;
if (vec[n1][n2] == '0')
{
floodfill(n1, n2, '0', c1,ss);
counter++;
}
if (vec[n1][n2] !=c1) return 0;
int ans = 1;
vec[n1][n2] = c2;
for (int i = 0; i < 4; i++)
ans = ans + floodfill2(n1 + d1[i], n2 + d2[i], c1, c2,ss);
return ans;
}
int main() {
int n1;
int n2;
int co = 1;
while (true)
{
cin >> n1;
cin >> n2;
if (n1 == 0 && n2 == 0)
break;
getchar();
int aa = 0;
for (int i = 0; i < n1; i++)
{
char s[300];
scanf("%s", s);
string g = "";
int a = strlen(s);
for (int j = 0; j <a; j++)
{
string temp = "";
if (s[j] == '0')
temp = "0000";
else if (s[j] == '1')
temp = "0001";
else if (s[j] == '2')
temp = "0010";
else if (s[j] == '3')
temp = "0011";
else if (s[j] == '4')
temp = "0100";
else if (s[j] == '5')
temp = "0101";
else if (s[j] == '6')
temp = "0110";
else if (s[j] == '7')
temp = "0111";
else if (s[j] == '8')
temp = "1000";
else if (s[j] == '9')
temp = "1001";
else if (s[j] == 'a')
temp = "1010";
else if (s[j] == 'b')
temp = "1011";
else if (s[j] == 'c')
temp = "1100";
else if (s[j] == 'd')
temp = "1101";
else if (s[j] == 'e')
temp = "1110";
else if (s[j] == 'f')
temp = "1111";
g =g+ temp;
}
vec[aa] = g;
aa++;
}
floodfill(0, 0, '0', '.',aa);
string ans = "";
for (int i = 0; i < aa; i++)
{
for (int j = 0; j < vec[0].length(); j++)
{
counter = 0;
if (vec[i][j] == '1')
{
floodfill2(i, j, '1', '.',aa);
if (counter == 0)
ans = ans + 'W';
else if (counter == 1)
ans = ans + 'A';
else if (counter == 2)
ans = ans + 'K';
else if (counter == 3)
ans = ans + 'J';
else if (counter == 4)
ans = ans + 'S';
else if (counter == 5)
ans = ans + 'D';
}
}
}
sort(ans.begin(), ans.end());
cout << "Case " << co << ": " << ans << endl;
co++;
}
}
它适用于此输入
6 25
0000000000000000000000000
0000000000000000000000000
00001fe0000000000007c0000
00003fe0000000000007c0000
0000000000000000000000000
0000000000000000000000000
但停止了这个
200 50
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10000000000000000000000000000000000000000000000000
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答案 0 :(得分：0)
您有以下代码：
string vec[200 + 5];
...
if (vec[n1][n2] != c1) return 0;
我无法看到您正在检查此数组是否永远不会超出范围，即代码尝试访问大于205的元素。
我希望通过你的大量投入，你可以摆脱债券。
一种简单的检查方法是运行调试版本。一个不错的debug c运行时库应该会给你一个明确的越界错误。
否则，您可以添加以下内容：
#define MAXSIZE 204
string vec[ MAXSIZE];
...
if( n1 >= MAXSIZE )
{
cout << "ERROR: Input too big\n";
exit(1);
}