Question

我有简单的Spring MVC应用程序，我想在我的Advice Controller类中找到404未找到的异常

配置：

   public class AppInitializer extends AbstractAnnotationConfigDispatcherServletInitializer {


    @Override
    protected Class<?>[] getServletConfigClasses() {
        return new Class<?>[]{WebConfig.class};
    }


    @Override
    protected Class<?>[] getRootConfigClasses() {
        return new Class<?>[]{RootConfig.class, SecurityConfig.class};
    }


    @Override
    protected String[] getServletMappings() {
        return new String[]{"/"};
    }


    @Override
    public void onStartup(ServletContext servletContext) throws ServletException {
        super.onStartup(servletContext);
        servletContext.addListener(new SessionListener());
        FilterRegistration.Dynamic encodingFilter = servletContext.addFilter("encodingFilter", new CharacterEncodingFilter());
        encodingFilter.setInitParameter("encoding", "UTF-8");
        encodingFilter.setInitParameter("forceEncoding", "true");
        encodingFilter.addMappingForUrlPatterns(null, true, "/*");
    }
}

控制器：

@Controller
@RequestMapping("/")
public class HomeController {
 @RequestMapping(value = "/error/", method = RequestMethod.GET)
    public String error(){return "error";}
}

ControllerAdvice：

@ControllerAdvice
public class AdviceController {

    @ExceptionHandler(MyOwnException.class)
    @ResponseStatus(value= HttpStatus.BAD_REQUEST)
    public String checkoutException(CheckoutException e, HttpServletRequest httpServletRequest)   {
                return "error";
    }
}

当我手动抛出MyOwnException但我无法捕获NoHandlerFound异常时，我可以捕获自己的异常。当没有控制器方法来处理请求时，我需要发送404错误代码和相应的error.jsp页面

Answer 1

如果您的网络应用程序使用web.xml，则非常简单 - 只需添加以下内容（假设使用 InternalResourceViewResolver ，前缀指向 WEB-INF 视图文件夹和后缀 .jsp ）。您也可以拥有其他错误代码的多个错误页面元素。

<error-page>
    <error-code>404</error-code>
    <location>/error</location>
</error-page>

如果您没有使用web.xml，则会更复杂，您必须定义并注册自己的ExceptionResolver。有关如何执行此操作的详细信息，请查看此spring.io blog article。

（评论后编辑）

如果你想抓住NoHandlerFound例外，首先要告诉Spring通过setting a flag in the DispatcherServlet directly抛出它。为此，在AppInitializer类中添加DispatcherServlet定义，以添加标志：

@Override
public void onStartup(ServletContext servletContext) throws ServletException {
    super.onStartup(servletContext);
    servletContext.addListener(new SessionListener());
    //BEGIN OF NEW CODE
    WebApplicationContext context = getContext();
    DispatcherServlet dispatcherServlet = new DispatcherServlet(context);
    //we did all this to set the below flag
    dispatcherServlet.setThrowExceptionIfNoHandlerFound(true);
    ServletRegistration.Dynamic dispatcher = servletContext.addServlet("DispatcherServlet",dispatcherServlet );
    //END OF NEW CODE
    FilterRegistration.Dynamic encodingFilter = servletContext.addFilter("encodingFilter", new CharacterEncodingFilter());
    encodingFilter.setInitParameter("encoding", "UTF-8");
    encodingFilter.setInitParameter("forceEncoding", "true");
    encodingFilter.addMappingForUrlPatterns(null, true, "/*");
}

然后，您可以直接在AdviceController：

中捕获NoHandlerFound异常

@ControllerAdvice
public class AdviceController {
    //..
    @ExceptionHandler(NoHandlerFoundException.class)
    public String dealWithNoHandlerFoundException(CheckoutException e, HttpServletRequest httpServletRequest)   {
                return "error";
    }
}

使用java配置在Spring MVC中进行404错误重定向

1 个答案: