Question

我尝试使用标题，但收到了此警告：

警告：无法修改标头信息 - 已发送的标头（输出始于 /Applications/XAMPP/xamppfiles/htdocs/PHP/adm/Axel.php:156）in 第243行/Applications/XAMPP/xamppfiles/htdocs/PHP/adm/Axel.php

    <?php
$username = $_GET['username'];
if ($_POST) {
    $con = mysql_connect("localhost", "inmoti6_myuser", "mypassword");

    if (!$con) {
        die('Could not connect: ' . mysql_error());
    }

    mysql_select_db("inmoti6_mysite", $con);

    $username = $_GET['username'];

    $username = mysql_real_escape_string($username);

    $users_comment = $_POST['comment'];

    $users_comment = mysql_real_escape_string($users_comment);

    $query = "INSERT INTO `inmoti6_mysite`.`comments` (`id`, `name`, `comment`,`timestamp`) VALUES (NULL, '$username', '$users_comment', CURRENT_TIMESTAMP);";

    if ($users_comment == "") {

        echo"Please write a comment.";
    } else {

        mysql_query($query);
        echo "<h2>Thank you for your Comment!</h2>";

        mysql_close($con);
    }
}
?>

<h1>This is page1.php</h1>


<div style='margin:20px; width:100px; height:100px; background:blue;'></div>


<?php
$con = mysql_connect("localhost", "inmoti6_myuser", "mypassword");

$username = $_GET['username'];


if (!$con) {
    die('Could not connect: ' . mysql_error());
}

mysql_select_db("inmoti6_mysite", $con);


$query = "SELECT * FROM `comments`";

$comments = mysql_query($query);

echo "<h1>User Comments</h1>";

while ($row = mysql_fetch_array($comments, MYSQL_ASSOC)) {
    $username = $_GET['username'];
    $name = $row['name'];
    $comment = $row['comment'];
    $timestamp = $row['timestamp'];

    $name = htmlspecialchars($row['name'], ENT_QUOTES);
    $comment = htmlspecialchars($row['comment'], ENT_QUOTES);

    echo "  <div style='margin:30px 0px;'>
Name: $name<br />
Comment: $comment<br />
Timestamp: $timestamp
</div>
";
}

mysql_close($con);
?>
<?php
$username = $_GET['username'];

echo "<form action='Axel.php?username=$username' method='post' submit=true>
Comment:<br />
<textarea name='comment' id='comment'></textarea><br />
<input type='submit' value='Submit' />  
</form>";
?>

如何刷新但不重新提交？

0 个答案: