Question

我是SQL的新手，我确信这更简单。我希望在桌面上获得最新记录，然后按状态计算最新记录。某些能力按状态和月/年返回计数

would be a bonus. 
So table is the following:
ID     STATUS     TIMESTAMP
1      ACTIVE     04/19/2016
1      PENDING    04/18/2016
2      ACTIVE     04/08/2016
2      PENDING    04/01/2016
3      PENDING    04/07/2016
4      PENDING    12/01/2015
5      CANCELLED  12/30/2015

当我运行查询时，我想要以下内容：

ACTIVE    04/2016 2
PENDING   04/2016 1 
CANCELLED 12/2015 1

我可以使用以下内容获取最新记录：

Select id,
    status,
    date  from (
Select TABLE_A, 
    status, 
    date,
    row_number() over (partition by id order by date Desc) col
From TABLE_A) ps
Where ps.col = 1;

感谢您提前耐心等待。

Answer 1

你大部分都在那里。其余的只是聚合：

select status, to_char(date, 'YYYY-MM') as yyyymm, count(*)
from (Select TABLE_A, status, date,
             row_number() over (partition by id order by date Desc) as seqnum
      From TABLE_A
     ) ps
Where seqnum = 1
group by select status, to_char(date, 'YYYY-MM') ;

Oracle SQL Developer查询 - 选择最近的记录并按另一列计数

1 个答案: