Question

我试图遍历我的数据库并显示每一行。我不知道我的代码有什么问题，但它根本没有显示任何内容......任何人都可以帮忙吗？

<?php

$players = mysql_query("SELECT * FROM users");
while ($row = mysql_fetch_assoc($players)) {
    $steamid = $row["name"];
    $profilename = $row["profilename"];
    $profileurl = $row["profileurl"];
    $avatar = $row["avatar"];
    $region = $row["region"];


?>


<p><?php echo $name ?></p>
<p>><?php echo $profilename ?></p>
<p>><?php echo $profileurl ?></p>
<p><?php echo $avatar ?></p>


<?php
}
?>

这是包含此文件的地方：

<?php include 'fetch_players.php'; ?>

Answer 1

下面给出了使用mysqli_*正确方法的示例。请注意评论： -

<?php
error_reporting(E_ALL); // check all type of error
ini_set('display_errors',1); // display those error
$connection = mysqli_connect('hostname','username','password','dbname'); // provide your db credentials here
$final_data = array(); // create empty array
if($connection){
    $players = mysqli_query($connection,"SELECT * FROM users");
    if($players){
        while ($row = mysqli_fetch_assoc($players)) {
            $final_data[$row['id']]['name'] = $row['name']; // assign values id wise to the array
            $final_data[$row['id']]['profilename'] = $row['profilename'];
            $final_data[$row['id']]['profileurl'] = $row['profileurl'];
            $final_data[$row['id']]['avatar'] = $row['avatar'];
            $final_data[$row['id']]['region'] = $row['region'];
        }
    }else{
        echo "query execution failed because of". mysqli_error($connection);
    }
}else{
  echo "db connection error because of". mysqli_connect_error();
}
?>

<?php 
if(count($final_data) >0){ // check array have some value or not?
foreach($final_data as $final_dat){?>
    <p><?php echo $final_dat['name'] ?></p><!-- print out values -->
    <p><?php echo $final_dat['profilename'] ?></p>
    <p><?php echo $final_dat['profileurl'] ?></p>
    <p><?php echo $final_dat['avatar'] ?></p>
    <p><?php echo $final_dat['region'] ?></p>
<?php }}?>

从数据库sql循环并显示多个表行

1 个答案: